The solutions of the equations of the situation can be:
z = 1 , y = 5, x = 4
z= 2 , y = 3, x = 5
z=3 , y = 1, x = 6
z = 0 , y = 7, x =3
The question can be expressed as a equation
6 x + 8 y + 10 z = 84
also, x + y + z = 10
⇒ x = 10- y - z
Putting it in first equation,
6(10 - y - z ) +8y + 10z = 84
⇒ 60 +2y + 4z = 84
⇒2(y + 2z ) = 14
⇒ y + 2z = 7
Now putting
z = 1 , we get y = 5,
z= 2 , y = 3
z=3 , y = 1
z = 0 , y = 7
So, only 4 possible solutions.
Therefore, there can only be 4 possible solutions for the equations.
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9 more than y is an expression so it would be 9+y
Answer:
A= X,B
B= L,G
C= M,W
The total number of combinations is 12
Step-by-step explanation:
Use Pythagorean theorem here. To find the height, find the difference of the 2 y's. To find the length, find the difference between the 2 x's.
Length = x2 - x1
Height = y2 - y1
√length^2 + height^2 = distance
√5^2 + 5^2 = √50 = 7.07
5x + 3y = 460
5(x + y = 120)
5x + 5y = 600
Use elimination subtraction
-2y = -140
y = 70
There are 70 student tickets
