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Stella [2.4K]
3 years ago
5

Triangle JKL is transformed by performing a 90degree clockwise rotation about the origin and then a reflection over the y-axis,

creating triangle J’’K’’L’’. Which transformation will map J’’K’’L’’ back to JKL?
A.) a reflection over the y-axis and then a 90degree clockwise rotation about the origin
B.) a reflection over the x-axis and then a 90degree counterclockwise rotation about the origin
C.) a reflection over the x-axis and then a 90degree clockwise rotation about the origin
D.) a reflection over the x-axis and then a reflection over the y-axis
Mathematics
1 answer:
marshall27 [118]3 years ago
4 0

Answer:

B

Step-by-step explanation:

Just do the reverse of what they did and you will always make it back to where you started. It's like someone saying, "take 2 steps forward then turn around.." how do you get back? You turn <em>back</em> around and take 2 steps <em>backward.</em>

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Hope this helped!  :D

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Plz help me out with this and do show work I will be waiting.... btw u will be marked brainliest!!!!!! Fast plz
pychu [463]

Answer:

x=16°

Step-by-step explanation:

5*x-30=2*(x+18)

For the second, I'd say it is:

5*x-30=2*x+18  

Let's solve both.  

5*x-30=2*(x+18)

5x-30=2x+36

3x=66

x=22  

5*x-30=2*x+18

3x+48

x=16°

8 0
3 years ago
A force of 50 pounds is exerted at an angle of 80 with the horizontal. What is its horizontal component?
Shalnov [3]

Answer:

Option A is the correct answer.

Explanation:

 Any vector can be resolved in to two components. Horizontal component and vertical component.

Consider a vector F which is at angle θ⁰ to the horizontal, we can resolve this vector in to two.

Horizontal component = F cos θ

Vertical component = F sin θ

Here we have Force , F = 50 pounds

Angle with horizontal = 80°

Horizontal component = F cos θ = 50* cos 80 = 8.68 pounds

                                      ≅ 9 lb.

Option A is the correct answer.

6 0
3 years ago
In triangle ABC, a = 9, c = 5, and angle B = 120°. Find the measure of angle A to the nearest degree. Show your work.
slamgirl [31]

<u>Answer:</u>

Angle A = 39°

<u>Step-by-step explanation:</u>

We are given that there is a triangle ABC where a = 9, c = 5 and angle B = 120° and we are to find the measure of angle A.

But first we need to find the side b using the law of cosine:

b^2 = a^2 + c^2- 2a*c*cos(120)

b^2 = 81 + 25 - 2*9*5*(-0.5)

b=\sqrt{151}

Now finding angle A using law of cosine:

cos(A) = \frac{b^2+c^2-a^2}{2b*c}

cos(A) = \frac{151+25-81}{2*12.29*5}

cos A=0.7730

A=39.38

Therefore, the measure of angle A = 39°.

7 0
3 years ago
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Answer:

Which One ?

Step-by-step explanation:

8 0
3 years ago
What is f(x) = 3log(x+5)=2
trasher [3.6K]

Answer:

x=10^{\frac{2}{3}}-5

Step-by-step explanation:

3 0
2 years ago
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