Answer: The motions shifts.
Answer:
The transverse wave will travel with a speed of 25.5 m/s along the cable.
Explanation:
let T = 2.96×10^4 N be the tension in in the steel cable, ρ = 7860 kg/m^3 is the density of the steel and A = 4.49×10^-3 m^2 be the cross-sectional area of the cable.
then, if V is the volume of the cable:
ρ = m/V
m = ρ×V
but V = A×L , where L is the length of the cable.
m = ρ×(A×L)
m/L = ρ×A
then the speed of the wave in the cable is given by:
v = √(T×L/m)
= √(T/A×ρ)
= √[2.96×10^4/(4.49×10^-3×7860)]
= 25.5 m/s
Therefore, the transverse wave will travel with a speed of 25.5 m/s along the cable.
Answer:
Explanation:Naturally occurring radioactive materials are present in its crust, the floors and walls of our homes, schools, or offices and in the food we eat and drink. There are radioactive gases in the air we breathe. Our own bodies - muscles, bones, and tissue - contain naturally occurring radioactive elements.
Answer:
t = 36π seconds
Explanation:
For resolving this problem, we are going to consider a representative stadium of the United States. The Mercedes-Benz Stadium located in Atlanta, Georgia has an average radius of 90 m.
Then, its circumference measures:
L = 2πr
L = 2π(90)
L = 180π m
First, we estimate the wave's velocity: the average width of an person is 0.5 m, then the velocity is:
v = x/t
Where x: person's width
t: time
v = 0.5/0.1 = 5 m/s
The time required for the pulse to make one circuit around the stadium is:
t = x/v = 180π/5 = 36π seconds
Density is defines as the ratio of mass to volume.
So you measure the mass and volume of a sample, and
divide the mass by the volume, to find the density.
