I believe the sun is the primary source of energy for Earth's weather system. The sun is the primary energy source for Earth's climate system which is the first set of essential principles of climate sciences. Additionally, it is the primary source that drives all weather events, including precipitation, hurricane and tornadoes. The sun drives the hydrologic cycle, and makes life on Earth possible.
<u>Answer</u>
48 Volts
<u>Explanation</u>
The question can be solve using the turn rule of a transformer that states;
Np/Ns = Vp/Vs
Where Np ⇒ number of turns in the primary coil.
Ns ⇒number of turns in the seconndary coil
Vp ⇒ primary voltage
Vs ⇒secondary voltage
Np/Ns = Vp/Vs
10/4 = 120/Vp
Vp = (120 × 4)/10
= 480/10
= 48 Volts
Answer:
Earth's crust is covered by a densed air blanket called atmosphere. Due to which we feel warm even during night when there is no sun. The air near the atmosphere is less dense compared to the air near our crust. Similarly we can experience high pressure near the atmosphere comparelatively we experience less pressure near crust. The presence of atmosphere above us makes the wind fair sometimes stromy and also helps in pteperation of wind and breezes in earth's surface.
<span>In order to calculate an average, we should sum all numbers and divide them by quantity.
Let’s work with qualifications first. Let’s say you got a 10 in 1 exam, then an 8 in 2 exams and a 4 in 2 exams. Your average will be:
= (10*1+8*2+4*2) / 5 = 6.8
If 6 is the minimum, you will pass.
There is another way to calculate this average: applying distributive property.
= 10*1/5+8*2/5+4*2/5 = 6.8
Remember you can convert the fractions into equivalent fractions: 1/5 = 20/100; 2/5 = 40/100
= 10*20/100+8*20/100+4*20/100 = 6.8
We actually don’t have the number of atoms of each mass… we have the percentage instead! So we need to learn this last method for atoms.
Let’s go back to our atoms problem:
73.71 % of atoms have a mass of 27.98 u
14.93 % of atoms have a mass of 28.98 u
11.36 % of atoms have a mass of 29.97 u
So let’s put that in the formula:
Average mass = 27.98 u*73.71 /100 + 28.98 u*14.93 /100 + 29.97u*11.36 /100
So what you have to know is that a percentage can be converted into a fraction, and you should work that fraction in order to find the average. We can make the calculus shorter putting 100 as the common denominator:
Average mass = (27.98 u*73.71 + 28.98 u*14.93 + 29.97u*11.36)/100
So actually we are taking the percentage as if it was the quantity, and 100 as if it was the total (the total of all percentages is always 100). Maybe we don’t have 100 atoms, but it will be the same proportion anyway, whatever number we have! And here it is the result:
Average mass = 28,36u
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Answer:
P( red | large shirt ) ≠ P( large shirt)
P( Blue | large shirt ) = P( blue shirt)
P( shirt is medium and blue ) ≠ P( medium shirt)
P( large shirt | red shirt ) ≠ P( red shirt)
Explanation:
P( red | large shirt ) = 42/77 = 0.5454 : P( large shirt)= 77/165 = 0.467
P( red | large shirt ) ≠ P( large shirt)
P( Blue | large shirt ) = 35/77 = 0.4545 : P( blue shirt)= 75/165 = 0.4545
P( Blue | large shirt ) = P( blue shirt)
P( Shirt is medium and blue ) = 40/77 = 0.2424 : P( medium shirt)= 88/165 = 0.5333
P( shirt is medium and blue ) ≠ P( medium shirt)
P( large shirt | red shirt) = 42/90 = 0.4667 : P( red shirt)= 90/165 = 0.5454
P( large shirt | red shirt ) ≠ P( red shirt)
