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leva [86]
3 years ago
8

the perimeter of square f is 2/3 less than the perimeter of square g . the side lengths of square f are each x meters , and the

sides of square g are each 1/4(x-2/3) meters. which expression also represents the side lengths of square g A 1/4x - 1/6 B 1/4f - 2/3 C 1/4f - 3/7 D 1/4x - 11/12​
Mathematics
2 answers:
iogann1982 [59]3 years ago
4 0

GIVEN:

  • Sides of square g = 1/4(x – 2/3)

ANSWER:

On simplyfying given sides,

1/4(x – 2/3)

  • 1/4x – 1/4 × 2/3
  • 1/4x – 1/6

And all other options are mismatch.

So, <u>Correct choice</u> - [A] 1/4x – 1/6

horrorfan [7]3 years ago
3 0

Answer:

  • A. 1/4x - 1/6

Step-by-step explanation:

  • 1/4(x - 2/3) =
  • 1/4x - 1/4(2/3) =
  • 1/4x - 1/6

Correct choice is A

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Three friends each have some ribbon. Carl has 54 inches of ribbon,Tino has 13.5 feet of ribbon, and Baxter has 3.5 yards of ribb
deff fn [24]

Answer:

  342 inches, or 28.5 feet, or 9.5 yards

Step-by-step explanation:

It is perhaps easiest to start with all the dimensions in inches.

  13.5 ft = (13.5 ft)(12 in/ft) = 162 in

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7 0
3 years ago
Find two rational expressions a / b and c / d that produce the result x − 1 / x2 when using the following operations. Answers
Mars2501 [29]

Answer:

a) Let \frac{a}{b}=\frac{-1}{x^2}, \text{ and } \frac{c}{d}=\frac{1}{x}.

Observe that

\frac{a}{b}+\frac{c}{d}=\frac{-1}{x^2}+\frac{1}{x}=\frac{-x+x^2}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}

b)

Let \frac{a}{b}=\frac{1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x^2}.

Observe that

\frac{a}{b}-\frac{c}{d}=\frac{1}{x}-\frac{1}{x^2}=\frac{x^2-x}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}

c)

Let \frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x}.

Observe that

\frac{a}{b}*\frac{c}{d}=\frac{x-1}{x}*\frac{1}{x}=\frac{(x-1)1}{x*x}=\frac{x-1}{x^2}

d)

Let \frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{x}{1}.

Observe that

\frac{a}{b}\div\frac{c}{d}=\frac{x-1}{x}\div\frac{x}{1}=\frac{x-1}{x}*\frac{1}{x}=\frac{x-1}{x^2}

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