A grocer wants to mix nuts costing 5.00 per kilogram with nuts costing 8.00 per kilogram to make a 10 kilogram mixture for 6.00
a kilogram. How much of each type should he mix.
2 answers:
Step-by-step explanation:
let E be weight of expensive nuts, C be cheaper nuts
E*8+C*5=10*6 value equation
E+C=10 mass equation
Solve it by any method, I will do determinants
Det: 8-5=3
E= (60-50)/3=10/3 =3.33 lb
C= 80-60 /3=20/3 =6.66 lb
Answer:
mix nuts 20/3
nuts 10/3=
Step-by-step explanation:
x+y=10
5x+8y=60
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