Answer:
Probability that a student chosen randomly from the class plays basketball or baseball is
or 0.76
Step-by-step explanation:
Given:
Total number of students in the class = 30
Number of students who plays basket ball = 19
Number of students who plays base ball = 12
Number of students who plays base both the games = 8
To find:
Probability that a student chosen randomly from the class plays basketball or baseball=?
Solution:
---------------(1)
where
P(A) = Probability of choosing a student playing basket ball
P(B) = Probability of choosing a student playing base ball
P(A \cap B) = Probability of choosing a student playing both the games
<u>Finding P(A)</u>
P(A) = 
P(A) =
--------------------------(2)
<u>Finding P(B)</u>
P(B) = 
P(B) =
---------------------------(3)
<u>Finding
</u>
P(A) = 
P(A) =
-----------------------------(4)
Now substituting (2), (3) , (4) in (1), we get


