Answer:
answer is b I think
Step-by-step explanation:
because it is
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
9 OK there you go
if you don't think this is correct then ask someone else
Answer:
x=-2/5
Step-by-step explanation:
4(-3x-1)=13x+6 ~ Distribute the 4 into the parenthesis
-12x-4 = 13x+6 ~ add 12x to both sides
-4= 25x + 6 ~ subtract 6 from both sides
-10 =25x ~ divide by 25
-10/25 = x ~ simplify the fraction by dividing the num. and den by 5
-2/5 =x
Its A) -67
plug the m and n values into the function and solve using pemdas.
5(-7)-2(-7+3)^2
-35-2(-4)^2
-35-2(16)
-35-32
-67
