![\log_a(\frac{1}{a^{3}}) \newline \log_a(1) - \log_a(a^{3}) \newline 0 - \log_a(a^{3}) \newline 0 - 3\log_a(a) \newline 0 - 3(1) \newline = -3](https://tex.z-dn.net/?f=%20%5Clog_a%28%5Cfrac%7B1%7D%7Ba%5E%7B3%7D%7D%29%20%5Cnewline%20%5Clog_a%281%29%20-%20%5Clog_a%28a%5E%7B3%7D%29%20%5Cnewline%200%20-%20%5Clog_a%28a%5E%7B3%7D%29%20%5Cnewline%200%20-%203%5Clog_a%28a%29%20%5Cnewline%200%20-%203%281%29%20%5Cnewline%20%3D%20-3%20)
Your final answer is d) -3.
Answer:
option 2
Step-by-step explanation:
The problem can be solved using Pythagoras' identity for a right triangle.
The angle between due East and due North is 90°
The solution here involves using the Cosine rule.
let x be the direct distance between house and office, then
x² = 17² + 21² - 2(17)(21)cos90° → option 2
Note that since cos90° = 0 the equation reduces to
x² = 17² + 21² ← Pythagoras' identity
Abd/ ACD WILL HELP YOU THRIOUGH THE PROBLEM
Answer: 6) 35 meters 7) Ф = 10°
<u>Step-by-step explanation:</u>
![6.\quad \tan\ 68^o=\dfrac{x}{14.3}\\\\\\.\quad 14.3 \tan\ 68^o=x\\\\.\quad 35\ meters =x](https://tex.z-dn.net/?f=6.%5Cquad%20%5Ctan%5C%2068%5Eo%3D%5Cdfrac%7Bx%7D%7B14.3%7D%5C%5C%5C%5C%5C%5C.%5Cquad%2014.3%20%5Ctan%5C%2068%5Eo%3Dx%5C%5C%5C%5C.%5Cquad%2035%5C%20meters%20%3Dx)
![7.\quad \sin \theta =\dfrac{0.7}{4.2}\\\\\\.\qquad \quad \theta=\sin ^{-1}\bigg(\dfrac{1}{6}\bigg)\\\\\\,\qquad \quad \theta =10^o](https://tex.z-dn.net/?f=7.%5Cquad%20%5Csin%20%5Ctheta%20%3D%5Cdfrac%7B0.7%7D%7B4.2%7D%5C%5C%5C%5C%5C%5C.%5Cqquad%20%5Cquad%20%5Ctheta%3D%5Csin%20%5E%7B-1%7D%5Cbigg%28%5Cdfrac%7B1%7D%7B6%7D%5Cbigg%29%5C%5C%5C%5C%5C%5C%2C%5Cqquad%20%5Cquad%20%5Ctheta%20%3D10%5Eo)
What is s three times greater than?