Ask question

Ask question

All categories

3 years ago

8

If h(x)=3^x-7 find h(4) show all work

xFormula1" title="h(x) = {3}^{x} - 7" alt="h(x) = {3}^{x} - 7" align="absmiddle" class="latex-formula">

2 answers:

natta225 [31]3 years ago

8 0

H(x) = (3^x) - 7
h(4) = (3^4) - 7 ... replace every x with 4; then use PEMDAS to simplify
h(4) = 81 - 7
h(4) = 74

Answer: 74

Side Note: 3^4 means we have four copies of '3' being multiplied together
3^4 = 3*3*3*3 = 9*9 = 81

Svetach [21]3 years ago

3 0

Just substitute 4 for x in the given equation:

h(4) = 3^4 - 7 = 81 - 7 = 74 (answer)

You might be interested in

What is the range of the function y = x² + 1?

Mazyrski [523]

Answer

[ 1 by 2, -1 by 2 ]

Step-by-step explanation:

https://haygot.s3.amazonaws.com/questions/1118559_1200733_ans_2ec06a240d2240e49dc1c9fda7b41ef5.jpeg

7 0

2 years ago

Read 2 more answers

What two numbers have a product of -22 and a sum of -9?

omeli [17]

Answer:

2 and -11

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Please solve with working thankyou

Lisa [10]

Answer:

m∠y=72°

Step-by-step explanation:

<u><em>The question is</em></u>

Find the measure of angle y

step 1

Find the measure of angle x

see the attached figure to better understand the problem

we know that

m∠x=67° -----> by corresponding angles

step 2

Find the measure of angle y

we know that

(m∠x+m∠y)+42°=180° -----> because form a straight line

substitute the measure of angle x

67°+m∠y+42°=180

m∠y+108°=180

m∠y=180°-108°

m∠y=72°

4 0

2 years ago

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

2 years ago

Patrick is driving form Sydney to Canberra. He travels for 288km trip in 4 hours. What's his average speed?

nika2105 [10]

Answer:

v = 72 km/h

Step-by-step explanation:

Given that,

The distance covered by the Patrick, d = 288 km

Time taken, t = 4 hours

We need to find the average speed of Patrick. We know that the average speed of an object is equal to the total distance covered divided by total time taken. Let it is v. So,

$v=\dfrac{d}{t}\\\\v=\dfrac{288\ km}{4\ h}\\\\v=72\ km/h$

So, his average speed is equal to 72 km/h.

3 0

2 years ago