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Marrrta [24]
3 years ago
14

What evidence can you cite to support the claim that the frequency of light does not change upon reflection?

Physics
1 answer:
sergiy2304 [10]3 years ago
5 0

Answer: The color of an image is identical to the color of the object forming the image. When you look at yourself in a mirror, the color of your eyes doesn’t change. The fact that the color is the same is evidence that the frequency of light doesn’t change upon reflection. 2.

Hope this helps!!

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A string is wrapped around a uniform disk of mass M = 1.2 kg and radius R = 0.07 m. (Recall that the moment of inertia of a unif
pentagon [3]

Explanation:

Given that,

Mass of disk = 1.2 kg

Radius = 0.07 m

Radius of rod = 0.11 m

Mass of small disk = 0.5 kg

Force = 29 N

Time t = 0.022 s

\theta=0.023\ m

Distance d= 0.039 m

(I). We need to calculate the speed of the apparatus

Using work energy theorem

W=\Delta K.E

Fd=\dfrac{1}{2}mv^2

v=\sqrt{\dfrac{2Fd}{M+4m}}

Where, m = total mass

v = velocity

F = force

d = distance

Put the value into the formula

v=\sqrt{\dfrac{2\times29\times0.039}{1.2+4\times0.5}}

v=0.840\ m/s

(b). We need to calculate the angular speed of the apparatus

Using formula of torque

\tau=I\alpha

F\times=(\dfrac{1}{2}MR^2+4mb^2)\alpha

29\times0.07=(\dfrac{1}{2}\times1.2\times0.07^2+4\times0.5\times0.11^2)\alpha

\alpha=\dfrac{29\times0.07}{0.02714}

\alpha=74.79\ rad/s^2

We need to calculate the angular speed of the apparatus

Using equation of angular motion

\omega=\omega_{0}+\alpha t

Put the value into the formula

\omega=0+74.79\times0.022

\omega=1.645\ rad/s

(c).  We need to calculate the angular speed of the apparatus

Using equation of angular motion

\omega_{0}^2=\omega^2+2\alpha t

Put the value into the formula

\omega_{0}^2=1.645^2+2\times74.79\times0.022

\omega=2.44\ rad/s

Hence, This is required equation.

7 0
3 years ago
An astronaut has a mass of 50.0 kg on earth. what is her mass on the moon, where gravity is 1 6 that on earth?
never [62]

I believe the correct gravity on the moon is 1/6 of Earth. Take note there is a difference between 1 6 and 1/6.

HOWEVER, we should realize that the trick here is that the question asks about the MASS of the astronaut and not his weight. Mass is an inherent property of an object, it is unaffected by external factors such as gravity. What will change as the astronaut moves from Earth to the moon is his weight, which has the formula: weight = mass times gravity.

<span>Therefore if he has a mass of 50 kg on Earth, then he will also have a mass of 50 kg on moon.</span>

6 0
4 years ago
You see lightning before you hear thunder because A) light waves can travel through a vacuum. B) sound waves cannot travel throu
Alex Ar [27]
C) light waves travel faster than sound waves

You were correct
3 0
4 years ago
Read 2 more answers
Which of Newton's Three Laws Applies? Law 1, 2, or 3?
frozen [14]

Answer:

1. Newton's first law

2.Newton's second law

3.Newton's third law

Explanation:

1. Newton's first law stated, In an inertial frame of reference, an object either remains at rest or continues to move at a constant velocity, unless acted upon by a force... this is base of the concept of inertia.

2. Newton's second law stated, In an inertial frame of reference, the vector sum of the forces F on an object is equal to the mass m of that object multiplied by the acceleration a of the object: F = ma, or in easier words, F is directly proportional to a.

3. Newton's third law stated, When one body exerts a force on a second body, the second body simultaneously exerts a force equal in magnitude and opposite in direction on the first body., In this case, the Normal Are opposite with gravititional force.

7 0
3 years ago
the electron are accelrated to a speed of 2.40*10^7 in 1.8*10^-9, the force experinced by an electron ?
dalvyx [7]
Force = mass × acceleration

To find acceleration, we can divide the speed by the time it took:

acceleration = 2.40×10^7 / 1.8×10^-9

acceleration = 1.33×10^16

the mass is equal to the mass of an electron

force = (9.11×10^-31)(1.33×10^16)

force = 1.21×10^-14 N
3 0
3 years ago
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