Question

PLEASE HELP ME WITH THIS ONE QUESTION

Answer 1

Explanation:

First, we convert the energy from eV to Joules:

$2.90\:\text{eV}×\left(\dfrac{1.6×10{-19}\:J}{1\:\text{eV}} \right)$

$= 4.64×10^{-19}\:\text{eV}$

We know from definition that

$E=h\nu = \dfrac{hc}{\lambda}$

so the wavelength of the photon is

$\lambda = \dfrac{hc}{E} = 4.28×10^8\:\text{m}$