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fenix001 [56]
2 years ago
9

Why are the orbits of planets only nearly circular and not perfectly circular?

Physics
1 answer:
Galina-37 [17]2 years ago
7 0

Explanation:

this is my answer this is helpful for you

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How does increasing the tension of a spring affect a wave on the spring?
Liono4ka [1.6K]
More energy is being used in the movement

8 0
3 years ago
Read 2 more answers
Consider the two vectors A = 3 î − ĵ and B = − î − 2 ĵ.
LUCKY_DIMON [66]

Answer:

(a) A+B = 2i-3j

(B) A-B = 4i + j

Explanation:

We have given two vectors A = 3i-j and B = -1-2j

We have to find the two vectors that is A+B and A-B

(A) In first art we have calculate A+B for this we have to add simply vector A and v ector B

So A+B = 3i-j-i-2j = 2i-3j

(B) In this part we have to find A-B for this we have to simply subtract B from A so A-B = 3i-j-(-i-2j) =3i-j+i+2j =4i+j

6 0
3 years ago
A textbook of mass 2.10 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose d
Lilit [14]

Answer:

the tension in the part of the cord attached to the textbook is 7.4989 N

Explanation:

Given the data in the question;

As illustrated in the image below;

first we determine the value of the acceleration,

along vertical direction; we use the second equation of motion;

y = ut + \frac{1}{2}a_yt²

we substitute;

0 m/s for u, 1.29 m for y, 0.850 s for t,

1.29 = 0×0.850  + \frac{1}{2}×a_y×(0.850)²

1.29 = 0.36125a_y

a_y = 1.29 / 0.36125

a_y = 3.5709 m/s²

Now when the text book is moving with acceleration , the dynamic equation will be;

T₁ = m₁a_y

where m₁ is the mass of the text book ( 2.10 kg )

a_y is the vertical acceleration ( 3.5709 m/s² )

so we substitute

T₁ = 2.10 × 3.5709

T₁ = 7.4989 N

Therefore, the tension in the part of the cord attached to the textbook is 7.4989 N

3 0
2 years ago
Increase 90 in the ratio 6 : 5​
Jobisdone [24]

Answer:

<em>108</em>

Explanation:

<u>Proportions </u>

Two quantities are proportional when one of them can be obtained by multiplying or dividing the other by a constant value. For example, knowing the price of one pencil as p, we can know the cost of purchasing X pencils as C=p.X

We are required to increase 90 by the ratio 6:5. The new value will be proportional to the original because we'll compute the product of

\displaystyle 90\ \frac{6}{5}=108

So the new value is 108

3 0
3 years ago
Calculate the resistance 50 feet of awg no. 12 solid copper wire round to nearest 0. 01 ohms.
emmasim [6.3K]

The resistance of the conductor is 0.07940 Ohms.

<h3>What is the relation between resistance and area of wire?</h3>

The wire's resistance is inversely related to its cross-sectional area; as the area drops, so does the resistance.

and it is formulated as:  

R=p\frac{l}{s}

where,

<em>p </em>- resistivity of the conductor (0.0214-ohm mm²/m)

R - resistance

l- length of conductor (50 feet) (15.24 m)

s - the area of the wire

Thus the resistance can be calculated as

R = 0.07940 Ohms.

Learn more about resistance here:

brainly.com/question/11431009

#SPJ4

6 0
2 years ago
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