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Setler [38]
3 years ago
11

Write the equation of the graph shown below in factored form.

Mathematics
1 answer:
VLD [36.1K]3 years ago
7 0

Answer:

a. f(x)=(x-2)^2(x+1)(x-3)

Step-by-step explanation:

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What is 27×1/3=?<br> please answer
sattari [20]
The answer is nine. You can write 27 as 27/1. From there, just multiply the fractions.

27/1 x 1/3 = 9
5 0
4 years ago
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3x+1/5 y= 7 solve for x
TiliK225 [7]
X = -1/15y+7/3

I hope this helps! :>
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4 years ago
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Please help someone..
snow_tiger [21]

Answer:  \bold{\dfrac{1}{5}}

<u>Step-by-step explanation:</u>

\dfrac{DF}{AK}=\dfrac{4}{20}=\large\boxed{\dfrac{1}{5}}

4 0
3 years ago
Write down in terms of n an expression for the nth term of the following sequences 9 11 13 15 17
zvonat [6]

Answer:

2n+7

Step-by-step explanation:

 +2  +2  +2  +2

9     11  13  15  17  so we start with 2n

2 ➡ 9 = +7   6 ➡ 13 = +7

4 ➡ 11 = +7   8 ➡ 15 = +7

So the answer is 2n + 7

5 0
3 years ago
Find the radius of convergence, then determine the interval of convergence
galben [10]

The radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series. This can be obtained by using ratio test.  

<h3>Find the radius of convergence R and the interval of convergence:</h3>

Ratio test is the test that is used to find the convergence of the given power series.  

First aₙ is noted and then aₙ₊₁ is noted.

For  ∑ aₙ,  aₙ and aₙ₊₁ is noted.

\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }| = β

  • If β < 1, then the series converges
  • If β > 1, then the series diverges
  • If β = 1, then the series inconclusive

Here a_{k} = \frac{(x+2)^{k}}{\sqrt{k} }  and  a_{k+1} = \frac{(x+2)^{k+1}}{\sqrt{k+1} }

   

Now limit is taken,

\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }| = \lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }/\frac{(x+2)^{k} }{\sqrt{k} }|

= \lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }\frac{\sqrt{k} }{(x+2)^{k}}|

= \lim_{n \to \infty} |{(x+2) } }{\sqrt{\frac{k}{k+1} } }}|

= |{x+2 }|\lim_{n \to \infty}}{\sqrt{\frac{k}{k+1} } }}

= |{x+2 }| < 1

- 1 < {x+2 } < 1

- 1 - 2 < x < 1 - 2

- 3 < x < - 1

 

We get that,

interval of convergence = (-3, -1)

radius of convergence R = 1

Hence the radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series.

Learn more about radius of convergence here:

brainly.com/question/14394994

#SPJ1

5 0
1 year ago
Read 2 more answers
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