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Setler [38]
2 years ago
11

Write the equation of the graph shown below in factored form.

Mathematics
1 answer:
VLD [36.1K]2 years ago
7 0

Answer:

a. f(x)=(x-2)^2(x+1)(x-3)

Step-by-step explanation:

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The side lengths, in centimeters, of a triangle are 5x, 32, and 2(3x + 2). perimeter of the triangle is 80 centimeters. what is
Lerok [7]

Answer:

20 cm

Step-by-step explanation:

5x + 32 + 6x + 4 = 80

11x + 36 = 80

11x = 44

x = 4

sides of triangle:

5(4) = 20 cm

32 cm

6(4) + 2 = 26 cm

4 0
2 years ago
Jynessa wants to order these fractions: 4/9, 2/3, 1/6, -2 1/2 What should she use as her common denominator?
IceJOKER [234]
4/9 , 2/3, 1/6, ....-2 1/2 = - 5/2

common denominator is 18
8 0
3 years ago
Read 2 more answers
If f(x)=3x and g(x)=1/x, what is the domain of (g o f)(x)?
Neko [114]

Here it is given that f(x)=3x and g(x)=1/x

We have to find the domain of (g o f)(x)

Now it is given that f(x) = 3x

and it is also given that g(x) = 1/x

so (g o f)(x) = g( f(x) ) = g( 3x )

which comes out to be 1 / 3x

The domain of the expression is all the real numbers except where the expression is undefined so the domain of the given expression is all real numbers except 0.

5 0
3 years ago
An electrician has a piece of wire that is 4 and 3/8 centimeters long. She divides the wire into pieces that are 1 and 2/3 centi
Vlada [557]

Answer:

She has approximately 3 pieces ( 2.625)

Step-by-step explanation:

To get the number of pieces, we need to divide the length of the wire by the individual length of the pieces.

To get the division done, it would be easier to convert what we have into improper fractions

For the piece of wire, the length which is 4 and 3/8 centimeters long will be 35/8 centimeters

while;

the individual length of each of the piece which is 1 and 2/3 centimeters long will be 5/3 centimeters

The number of pieces is thus 35/8 divided by 5/3 = 35/8 * 3/5 = 21/8 = 2.625 which is approximately 3 pieces

6 0
3 years ago
4) Solve each pair of simultaneous equations.
Mkey [24]
4) a. x+y=1–(1)
y=2x-8—(2)
(2) into (1)
x+(2x-8)=1
3x-8=1
3x=1+8
x=9/3
x=3—(3)
(3) into (2)
y=2(3)-8
y=-2

ans x=3, y=-2

b. x+y=19—(1)
y=5x+1—(2)

(2) into (1)

x+(5x+1)=19
6x+1=19
6x=19-1
x=18/6
x=3—(3)

(3) into (2)

y=5(3)+1
y=16

ans x=3, y=16

c.x+y=-2—(1)
y=x-10—(2)

(2) into (1)

x+(x-10)=-2
2x-10=-2
2x=-2+10
x=8/2
x=4–(3)

(3) into (2)
y=4-10
y=-6

ans x=4, y=-6


5) 3x=y—(1)
x=y-16–(2)

(2) into (1)

3(y-16)=y
3y-48=y
2y=48
y=48/2
y=24–(3)

(3) into (2)

x=24-16
x=8

ans x=8, y=24
7 0
2 years ago
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