Answer:
6.75 moles of Ba(NO₃)₂.
Explanation:
The balanced equation for the reaction is given below:
3BaCl₂ + 2Al(NO₃)₃ —> 3Ba(NO₃)₂ + 2AlCl₃
From the balanced equation above,
2 moles of Al(NO₃)₃ reacted to produce 3 moles of Ba(NO₃)₂
Finally, we shall determine the number of mole of Ba(NO₃)₂ produced by the reaction of 4.25 moles of Al(NO₃)₃. This can be obtained as illustrated below:
From the balanced equation above,
2 moles of Al(NO₃)₃ reacted to produce 3 moles of Ba(NO₃)₂.
Therefore, 4.25 moles of Al(NO₃)₃ will react to produce = (4.50 × 3)/2 = 6.75 moles of Ba(NO₃)₂.
Thus, 6.75 moles of Ba(NO₃)₂ were obtained from the reaction.
