A lone pair is a pair of valence electrons that are not shared with another atom and is sometimes called a non-bonding pair.
<u>Answer:</u> The molarity of solution is 13.175 M.
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:

We are given:
Mass of solute (sodium hydroxide) = 527 g
Molar mass of sodium hydroxide = 40 g/mol
Volume of solution = 1 L
Putting values in above equation, we get:

Hence, the molarity of solution is 13.175 M.
I'll firstly separate the options for the answer so the question is more clear:
a) Their potential energies are the same because they have the same mass.
b) Potential energy doesn't depend on an object's relative height.
c) The ball at the top of the 5 foot hill has more potential energy.
d) The ball at the top of the 5 foot hill has less potential energy.
If we look at the equation for gravitational potential energy:
GPE = mgh
GPE = gravitational potential energy
m = mass of the object
g = gravitational constant
h = height of the object
We can see that GPE and height have a direct linear relationship. Therefore, as the height increases, the potential energy increases. This relationship suggests that since the mass is equal, the ball at the top of the 10 ft hill will have more potential energy than the ball at the top of the 5 ft hill.
The answer we are looking for is d) The ball at the top of the 5 foot hill has less potential energy.
Answer:
Enthalpy of formation to the nearest KJ = -275KJ
Explanation:
Enthalpy of formation is the heat change when one mole of a substance is formed from its element in its standard states and in standard conditions of temperature and pressure. it may be positive or negative, if positive, it is an endothermic reaction where the heat content of the product is greater than that of the reactants. and if negative, it is exothermic reaction - where the heat content of the reactants is greater than the products. the enthalpy of formation is measured in Kilo-Joule/Moles (KJ/Mole).
A detailed step by step calculation of the enthalpy of formation of one mole lead (II) sulfate of is attached below.