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GuDViN [60]
4 years ago
9

What is the ph of a saturated solution of aluminum hydroxide?

Chemistry
1 answer:
sasho [114]4 years ago
6 0
Answer is attached  below ( sorry for mistake )

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Ionization energy is the energy required to remove the outermost electron from one mole of gaseous atom to produce 1 mole of gaseous in to produce a charge of 1. The greater the ionization energy, the greater is the chance f the electron to be removed from the nucleus. In this casse, Radium has the largest ionization energy.

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6) Which country is located south of New Mexico<br> and Arizona?
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Which part of an atom is actively exchanged or shared in a chemical bond?
denpristay [2]

The part of an atom that is actively exchanged or shared in a chemical bond is ELECTRON.

An atom is made up of three sub particles, which are electron, proton and neutron. The proton and the neutron are located in the nucleus of the atom and they make up the major mass of the atom. The electron is located outside of the nucleus and it orbit around the nucleus; it has negligible mass. The electron is negatively charged and because it is located outside of the nucleus, it is the one that is always involved in chemical reactions. There are different types of chemical bonds in chemical compounds and it is electrons that are normally used to form these bonds. During bond formation, electrons can either be donated or shared.

5 0
3 years ago
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What is the mass in grams of 85.32 mL of blood plasma with a density of 1.03 g/mL
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3 0
3 years ago
Arbon dioxide is dissolved in blood (ph 7.5) to form a mixture of carbonic acid and bicarbonate. Part a neglecting free co2, wha
Aleks04 [339]

Answer : The fraction of carbonic acid present in the blood is 5.95%

Explanation :

The mixture consists of carbonic acid ( H₂CO₃) and bicarbonate ion ( HCO₃⁻). This represents a mixture of weak acid and its conjugate which is a buffer.

The pH of a buffer is calculated using Henderson equation which is given below.

pH = pKa + log \frac{[Base]}{[Acid]}

We have been given,

pH = 7.5

pKa of carbonic acid = 6.3

Let us plug in the values in Henderson equation to find the ratio Base/Acid.

7.5 = 6.3 + log \frac{[base]}{[acid]}

1.2 = log \frac{[base]}{[acid]}

\frac{[Base]}{[Acid]} = 10^{1.2}

\frac{[Base]}{[Acid]} = 15.8

[Base] = 15.8 \times [Acid]

The total of mole fraction of acid and base is 1. Therefore we have,

[Acid] + [Base] = 1

But Base = 15.8 x [Acid]. Let us plug in this value in above equation.

[Acid] + 15.8 \times [Acid] = 1

16.8 [Acid] = 1

[Acid] = \frac{1}{16.8}

[Acid] = 0.0595

[Acid] = 0.0595 x 100 = 5.95 %

The fraction of carbonic acid present in the blood is 5.95%

4 0
4 years ago
Read 2 more answers
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