Explanation:
Show that the motion of a mass attached to the end of a spring is SHM
Consider a mass "m" attached to the end of an elastic spring. The other end of the spring is fixed
at the a firm support as shown in figure "a". The whole system is placed on a smooth horizontal surface.
If we displace the mass 'm' from its mean position 'O' to point "a" by applying an external force, it is displaced by '+x' to its right, there will be elastic restring force on the mass equal to F in the left side which is applied by the spring.
According to "Hook's Law
F = - Kx ---- (1)
Negative sign indicates that the elastic restoring force is opposite to the displacement.
Where K= Spring Constant
If we release mass 'm' at point 'a', it moves forward to ' O'. At point ' O' it will not stop but moves forward towards point "b" due to inertia and covers the same displacement -x. At point 'b' once again elastic restoring force 'F' acts upon it but now in the right side. In this way it continues its motion
from a to b and then b to a.
According to Newton's 2nd law of motion, force 'F' produces acceleration 'a' in the body which is given by
F = ma ---- (2)
Comparing equation (1) & (2)
ma = -kx
Here k/m is constant term, therefore ,
a = - (Constant)x
or
a a -x
This relation indicates that the acceleration of body attached to the end elastic spring is directly proportional to its displacement. Therefore its motion is Simple Harmonic Motion.
Answer: Fmax = 5.54*10^-12 N
Explanation: From the question, we have the potential difference (V) =20kv = 20,000v and strength of magnetic field (B) =0.41 T.
The maximum force experienced by a charge of magnitude (q) is given as
Fmax = qvB
Where v = velocity of electron.
The velocity of the electron can be gotten by using the work energy theorem.
The kinetic energy of the electron (mv²/2) equals the work done needed to accelerate it.
mv²/2 = qV.
Where m = mass of an electronic charge = 9.11×10^-31 kg, q = magnitude of an electronic charge = 1.609×10^-19 c, v = velocity of electron, V = potential difference = 20,000v.
By substituting the parameters, we have that
(9.11×10^-31 × v²)/2 = 1.609×10^-19 × 20000
(9.11×10^-31 × v²) = 1.609×10^-19 × 20000 ×2
v² = (1.609×10^-19 × 20000 ×2)/9.11×10^-31
v² = 64.36*10^(-16)/9.11×10^-31
v² = 7.0647×10^15
v = √7.0647×10^15
v = 8.40×10^7 m/s
Fmax = 1.609×10^-19 × 8.40×10^7 × 0.41
Fmax = 5.54*10^-12 N
It means there are two chlorine molecules and there is only one magnesium molecule (because no subscript really just means there is an invisible 1 that isn't listed).
Answer:
<em>Hewo Otaku Kun Here! (UwU)</em>
Explanation:
1. A rock sitting at the edge of a cliff has potential energy. If the rock falls, the potential energy will be converted to kinetic energy.
2. Tree branches high up in a tree have potential energy because they can fall to the ground.
3. A stick of dynamite has chemical potential energy that would be released when the activation energy from the fuse comes into contact with the chemicals.
4. The food we eat has chemical potential energy because as our body digests it, it provides us with energy for basic metabolism.
5. A stretched spring in a pinball machine has elastic potential energy and can move the steel ball when released.
6. When a crane swings a wrecking ball up to a certain height, it gains more potential energy and has the ability to crash through buildings.
7. A set of double "A" batteries in a remote control car possess chemical potential energy which can supply electricity to run the car.
<em>happy to help!</em>
<em>from: Otaku Kun ^^</em>
Answer:
A car accelerating to the right
Explanation:
The free-body diagram shows all the forces acting on an object. The length of each arrow is proportional to the magnitude of the force represented by that arrow.
In this free-body diagram, we see that there are 4 forces acting on the object, in 4 different directions. We also see that the two vertical forces are equal so they are balanced, while the force to the rigth is larger than the force to the left: this means that there is a net force to the right, so the object is accelerating to the right.
Therefore, the correct answer is:
A car accelerating to the right
