Is 250 000 miles from the earth to the moon" is a qualitative<br> Observation<br> TRUE<br> Or false

9. A sports car travels on a straight road at 22.0 km/h and increases its speed to 57.0 km/h in

Varvara68 [4.7K]

Answer:

4.4 M/s

Explanation:

6 0

2 years ago

What current flows through a 2.56-cm-diameter rod of pure silicon that is 20.0 cm long, when 1.00 ✕ 103 V is applied to it? (Suc

vfiekz [6]

Answer:

Current, I = 0.0011 A

Explanation:

It is given that,

Diameter of rod, d = 2.56 cm

Radius of rod, r = 1.28 cm = 0.0128 m

The resistivity of the pure silicon, $\rho=2300\ \Omega-m$

Length of rod, l = 20 cm = 0.2 m

Voltage, $V=1\times 10^3\ V$

The resistivity of the rod is given by :

$R=\rho\dfrac{L}{A}$

$R=2300\ \Omega-m\dfrac{0.2\ m}{\pi (0.0128\ m)^2}$

R = 893692.30 ohms

Current flowing in the rod is calculated using Ohm's law as :

V = I R

$I=\dfrac{V}{R}$

$I=\dfrac{10^3\ V}{893692.30\ \Omega}$

I = 0.0011 A

So, the current flowing in the rod is 0.0011 A. Hence, this is the required solution.

6 0

3 years ago

In the average US household, the television is on 6.75 hours/day! How many hours will have passed after 77.7 years (the average

Nady [450]

Answer:

191433.4 hours

Explanation:

We are given that In the average US household, the television is on 6.75 hours/day! How many hours will have passed after 77.7 years (the average lifeexpectancy of an American)?

1 year - 365 days

Given that the television is on 6.75 hours/day.

If 1 year = 365 days

Convert 77.7 years to days by multiplying it by 365

77.7 × 365 = 28360.5 days

So the number of hours will be:

28360.5 × 6.75 = 191433.375 hours

Therefore, 191433.4 hours will pass.

Non of the options is correct.

6 0

3 years ago

Electrons are emitted from a surface when light of wavelength 500 nm is shone on the surface but electrons are not emitted for l

liberstina [14]

Explanation:

Given: $\lambda = 500\:\text{nm} = 5×10^{-7}\:\text{m}$

$\nu = \dfrac{c}{\lambda} = \dfrac{3×10^8\:\text{m/s}}{5×10^{-7}\:\text{m}}$

$\:\:\:\:\:= 6×10^{14}\:\text{Hz}$

The work function $\phi$ is then

$\phi = h\nu = (6.626×10^{-34}\:\text{J-s})(6×10^{14}\:\text{Hz})$

$\:\:\:\:\:\:\:= 3.98×10^{-19}\:\text{J}$

3 0

2 years ago

You accelerate a 0.43kg football 5m/s2. Calculate the force you applied to the football.

Elza [17]

The force applied on the football is 2.15 Newton.

Given the data in the question;

Mass of football; $m = 0.43kg$

Acceleration; $a = 5m/s^2$

Force applied; $F = \ ?$

To determine the force applied on the football, we use Newton's laws of motion:

$F = m * a$

Where m is the mass of the object and a is the acceleration.

We substitute our given values into the equation

$F = 0.43kg\ *\ 5m/s^2\\\\F = 2.15kg.m/s^2\\\\F = 2.15N$

Therefore, the force applied on the football is 2.15 Newton.

Learn more: brainly.com/question/2388393

7 0

2 years ago

Is 250 000 miles from the earth to the moon" is a qualitative Observation TRUE Or false