All categories

3 years ago

Is 250 000 miles from the earth to the moon" is a qualitative Observation TRUE Or false

Physics

1 answer:

lys-0071 [83]3 years ago

3 0

Answer:

True

Explanation:

You might be interested in

A car company is performing brake tests on one of its cars. The car reaches a speed of 160 km/h and then hits the brakes to slow

stellarik [79]

Answer:

a) t = 4.04 s , b) x = 89.77 m

Explanation:

This is a one-dimensional kinematics exercise.

a) Let's use caution to find the time, the vehicle speed when stopped is zero

v = v₀ - at

let's reduce the magnitudes to the SI system

v₀ = 160 km /h (1000m / 1km) (1h / 3600s) = 44.44 m / s

0 = v₀ - at

t = v₀ / a

t = 44.44 / 11

t = 4.04 s

b) to calculate the distance traveled we use

x = v₀t - ½ a t²

x = 44.44 4.04 - ½ 11.0 4.04²

x = 179.54 - 89.77

x = 89.77 m

6 0

3 years ago

Based on the pattern of reflections shown below, which of the following statements must be true?

beks73 [17]

Answer:

Explanation:

jehwrbuhbfohlefnlebflkqbefkhbwefvohbwfuhvbohbcjsh

3 0

3 years ago

Which policy might help eliminate a disadvantage of renewable energy resources? A. modernizing coal power plants B. storing nucl

Viefleur [7K]

I believe the answer is D

3 0

4 years ago

Wilbur ran 1-kilometer. Then he ran 500 meters. How many meters did Wilbur run all together?

Blababa [14]

The answer is B 1,500 meters since 1 kilometer to meters is 1,000 and u add the 500

8 0

3 years ago

A 2-m long string is stretched between two supports with a tension that produces a wave speed equal to vw=50.00m/s. What are the

svetoff [14.1K]

Answer

given,

Length of the string, L = 2 m

speed of the wave , v = 50 m/s

string is stretched between two string

For the waves the nodes must be between the strings

the wavelength is given by

$\lambda = \dfrac{2L}{n}$

where n is the number of antinodes; n = 1,2,3,...

the frequency expression is given by

$f = n\dfrac{v}{2L}$

now, wavelength calculation

n = 1

$\lambda_1 = \dfrac{2\times 2}{1}$

λ₁ = 4 m

n = 2

$\lambda_2 = \dfrac{2\times 2}{2}$

λ₂ = 2 m

n =3

$\lambda_3 = \dfrac{2\times 2}{3}$

λ₃ = 1.333 m

now, frequency calculation

n = 1

$f = n\dfrac{v}{2L}$

$f_1 =1\times \dfrac{50}{2\times 2}$

f₁ = 12.5 Hz

n = 2

$f = n\dfrac{v}{2L}$

$f_2 =2\times \dfrac{50}{2\times 2}$

f₂= 25 Hz

n = 3

$f = n\dfrac{v}{2L}$

$f_3 =3\times \dfrac{50}{2\times 2}$

f₃ = 37.5 Hz

8 0

3 years ago