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3 years ago

PLEASE HELP!!

Physics

1 answer:

leva [86]3 years ago

5 0

Answer:

C 1.67 × 10-9 N

Explanation:

The magnitude of the gravitational force between two objects is given by:

$F=G\frac{m_1 m_2}{r^2}$

where

G is the gravitational constant

m1 ,m2 are the masses of the two objects

r is their separation

In this problem, we have:

$m_1 = m_2 = 15.0 kg$

r = 3.00 m

Substituting into the equation, we find

$F=(6.67\cdot 10^{-11}) \frac{(15)(15)}{3.00^2}=1.67\cdot 10^{-9} N$

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A friend asks you how much pressure is in your car tires. You know that the tire manufacturer recommends 30 psi, but it's been a

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Answer:

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3 years ago

If at 10m above the ground an object has 50J of Kinetic Energy, with 50J of Potential Energy. How high can the object travel?

steposvetlana [31]

Hi there!

$\large\boxed{\text{B) 20 meters}}$

We know that:

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K = Kinetic Energy (J)

E = Total Energy (J)

At 10m, the total amount of energy is equivalent to:

U + K = 50 + 50 = 100 J

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2 years ago

What is the volume of a bar of soap that is 9 cm long, 5 cm wide, and 2 cm high?

GalinKa [24]

Answer:

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3 years ago

Read 2 more answers

Sheila weighs 60 kg and is riding a bike. Her momentum on the bike is 340 kg • m/s. The bike hits a rock, which stops it complet

Vikki [24]

Answer:

v₂ = 5.7 m/s

Explanation:

We will apply the law of conservation of momentum here:

$Total\ Initial\ Momentum = m_{1}v_{1} + m_{2}v_{2}\\$

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Total Initial Momentum = 340 kg.m/s

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v₁ = final speed of bike = 0 m/s

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v₂ = final speed of Sheila = ?

Therefore,

$340\ kg.m/s = m_{1}(0\ m/s) + (60\ kg)v_{2}\\v_{2} = \frac{340\ kg.m/s}{60\ kg}\\\\$

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3 years ago