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Nimfa-mama [501]
3 years ago
13

PLEASE HELP!!

Physics
1 answer:
leva [86]3 years ago
5 0

Answer:

C  1.67 × 10-9 N

Explanation:

The magnitude of the gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1 ,m2 are the masses of the two objects

r is their separation

In this problem, we have:

m_1 = m_2 = 15.0 kg

r = 3.00 m

Substituting into the equation, we find

F=(6.67\cdot 10^{-11}) \frac{(15)(15)}{3.00^2}=1.67\cdot 10^{-9} N

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A harmonic wave on a string with a mass per unit length of 0.050 kg/m and a tension of 60 N has an amplitude of 5.0 cm. Each sec
Dennis_Churaev [7]

Answer:

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6 0
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1. Two-point charges, QA = +8 μC and QB = -5 μC, are separated by a distance r = 10 cm. What is the magnitude and direction of t
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Explanation:

Charges,q_1=8\ \mu C=8\times 10^{-6}\ C

q_2=-5\ \mu C=-5\times 10^{-6}\ C

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We need to find the magnitude and direction of the electric force. It is given by :

F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times 8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\\\F=36\ N

So, the required force between charges is 36 N and it is towards positive charge i.e. +8 μC.

6 0
3 years ago
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