Why does a slinky wave eventually stop? Where did the energy go?

Physics

2 answers:

ipn [44]3 years ago

7 0

Answer:

A wave as seen above will start losing energy by transferring it to kinetic and rotational energy at the shallow bottom including sand transfers, which finally will become heat (extra kinetic energy). ... In the end all energy will end up as a higher temperature in the region and ground than if the ocean were calm.

Explanation:

plz mark me has brainlist

lubasha [3.4K]3 years ago

6 0

Answer:

Grades ... gravity affects them and the potential energy is converted into kinetic energy. Watching a Slinky move down the stairs or vibrating while ... and kinetic energy, and finally into sound waves.

Explanation:

You might be interested in

A typical laboratory centrifuge rotates at 4000 rpm. Test tubes have to be placed into a centrifuge very carefully because of th

cestrela7 [59]

Answer:

1. $a_{rad}=17545.2\frac{m}{s^{2}}$

2. $a=4429.45 \frac{m}{s^{2}}$

Explanation:

Radial acceleration is:

$a_{rad}=\frac{v^2}{r}$ (1)

With r the radius respects the axis of rotation and v the tangential velocity that is related with angular velocity (ω) by:

$v= \omega r$ (2)

By (2) on (1):

$a_{rad}= \frac{(\omega r)^2}{r}= (\omega )^2r=(418,88\frac{rad}{s})^2(0.1m)$

$a_{rad}=17545.2\frac{m}{s^{2}}$

To find the acceleration of the tube with the fall, we can use the expression:

$\overrightarrow{J}=\overrightarrow{F}_{avg}(\varDelta t)$ (3)

Due impulse-momentum theorem:

$\overrightarrow{J}=\overrightarrow{p}_{f}-\overrightarrow{p}_{i}$ (4)

with p the momentum and J the impulse. By (4) on (3):

$\overrightarrow{p}_{f}-\overrightarrow{p}_{i}=\overrightarrow{F}_{avg}(\varDelta t)$

And using Newton's second law (F=ma) and that (P=mv):

$mv_f-mv_i=(ma)(\varDelta t)$ (5)

Final velocity is the velocity just after the encounter with hard floor, and initial momentum us just before that moment so the first one is zero and the second one can be found sing conservation of energy:

$\frac{mv_i}{2}=mgh$