Answer:
0.17724 m/s²
Explanation:
D = Diameter of roll = Length of wing = 11 m
T = Time it takes to complete the circle = 35 s
Velocity

Acceleration

Acceleration of the tip of the plane is 0.17724 m/s²
Answer:
This is the answer: The speed of a proton is about 5.0 × 10⁵ m/s
Explanation:
Because of the speeds of protons! :D
Answer:

Explanation:
Given that,
The compression in the spring, x = 0.0647 m
Speed of the object, v = 2.08 m/s
To find,
Angular frequency of the object.
Solution,
We know that the elation between the amplitude and the angular frequency in SHM is given by :

A is the amplitude
In case of spring the compression in the spring is equal to its amplitude



So, the angular frequency of the spring is 32.14 rad/s.
<span>We can answer this using
the rotational version of the kinematic equations:</span><span>
θ = θ₀ + ω₀<span>t + ½αt²
-----> 1</span></span>
ω² = ω₀² + 2αθ
-----> 2
Where:
θ = final angular
displacement = 70.4 rad
θ₀ = initial
angular displacement = 0
ω₀ = initial angular
speed
ω = final angular speed
t = time = 3.80 s
α = angular acceleration
= -5.20 rad/s^2
Substituting the values
into equation 1:<span>
70.4 = 0 + ω₀(3.80)
+ ½(-5.20)(3.80)² </span><span>
ω₀ = (70.4
+ 37.544) / 3.80 </span><span>
ω₀ = 28.406
rad/s </span><span>
Using equation 2:
ω² = (28.406)² + 2(-5.2)70.4
ω = 8.65 rad/s
</span>
Answer:
553.1m
Explanation:
When an object moves at constant velocity we can express this movement like V=x/t, where V is the velocity, x is the displacement and t is the time spent on it.
In that way, the expression x=V.t give us the displacement from t=0s until t=51s, but we have to sum the initial distance from the point A.
x=242m +V.t = 242m + (6.1m/s x 51s) = 553.1m