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TiliK225 [7]
3 years ago
14

A body starts initially at rest, starts moving with a constant acceleration of 2m/s2. Calculate the velocity acquired and the di

stance travelled in 5 s.​
Physics
1 answer:
dybincka [34]3 years ago
4 0

Answer:

10 m/s

Explanation:

Since acceleration is rate of change of speed per unit time and we know the initial velocity is zero then (v-u)/t= a hence v=at where v is the final velocity, u is initial velocity which is zero, t is time and a is acceleration. Substituting the value of acceleration with 2m/s2 and t for 5 s then

V= 5*2=10 m/s

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A 75 kg bungee jumper leaps from a bridge. When he is 30 meters above the water, and moving at a speed of 20 m/s, the bungee cor
jasenka [17]

Answer:

k = 52.2 N / m

Explanation:

For this exercise we are going to use the conservation of mechanical energy.

Starting point. When it is 30 m high

        Em₀ = K + U = ½ m v² + m g h

Final point. Right when you hit the water

        Em_{f} = K_{e} = ½ k x²

in this case the distance the bungee is stretched is 30 m

        x = h

as they indicate that there are no losses, energy is conserved

        Em₀ = Em_{f}

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let's calculate

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3 0
3 years ago
4. Many of the teachers think that if a student sleeps more on the night before the test, then they
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8 0
1 year ago
A wire carrying a 30.0-A current passes between the poles of a strong magnet that is perpendicular to its field and experiences
Zanzabum

Answer:

1.79 T

Explanation:

Applying,

F = BILsin∅................ Equation 1

Where F = Force, B = magnetic field, I = current flowing through the wire, L = length of the wire, ∅ = angle between the magntic field and the force

make B the subject of the equation

B = F/ILsin∅............. Equation 2

From the question,

Given: F = 2.15 N, I = 30 A, L = 4.00 cm = 0.04 m, ∅ = 90° (perpendicular to the field)

Substitute these values into equation 2

B = 2.15/(30×0.04×sin90°)

B = 2.15/1.2

B = 1.79 T

Hence the average field strength is 1.79 T

8 0
3 years ago
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