A.) y = ut - 1/2gt^2 + 12
y = 6t - 1/2(9.8)t^2 + 12
y = 6t - 4.9t^2 + 12
b.) The y-intercept is 12
c.) The y-intercept represent the height of the ball at time t = 0
d.) At the time the ball reaches the ground, y = 0
-4.9t^2 + 6t + 12 = 0
t = 2.29 seconds
Therefore, it took the ball 2.29 seconds to reach the ground.
If i remember correctly i think you just cross multiply <span />
This is the answer for the calculation
3. is SAS
4. is CPCTC
5. i think its 66
Answer:15. 5/8 = 0.625
Step-by-step explanation:
