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OLga [1]
3 years ago
12

Find the height of the tower using the information given in the illustration. A right triangle has a a vertical side as the heig

ht of the Eiffel Tower, a horizontal side of length 130 feet across the ground, and an unlabeled hypotenuse. The angle formed by the hypotenuse and the horizontal side measures 85.691 degrees. 130 ft The height of the tower is nothing feet.
Mathematics
1 answer:
ollegr [7]3 years ago
4 0

Answer:

1725.1 feet

Step-by-step explanation:

It is given that there is a right angled triangle having a base of length of 130 feet. The angle between the hypotenuse and the base is given as 85.691 degrees.

Therefore, to find the height, we know :

$\tan \theta = \frac{\text{height}}{\text{base}}$

$\tan 85.691 = \frac{\text{h}}{\text{130}}$

$13.27 = \frac{\text{h}}{\text{130}}$

h = 13.27 x 130

  = 1725.1 feet

Therefore, the height of the Eiffel tower =  1725.1 feet

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PLEASE HELP ME OUT...
e-lub [12.9K]

Answer:

y=-3

Step-by-step explanation:

there is no slope so x will not be used in the equation it also crosses at -3

3 0
3 years ago
A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so
Debora [2.8K]

Let A(t) = amount of salt (in pounds) in the tank at time t (in minutes). Then A(0) = 11.

Salt flows in at a rate

\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}

and flows out at a rate

\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}

which I'll solve with the integrating factor method.

\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95

-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}

\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}

Integrate both sides. By the fundamental theorem of calculus,

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)

\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}

\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}

\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}

After 1 hour = 60 minutes, the tank will contain

A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131

pounds of salt.

7 0
1 year ago
Find the product of<br>the sum of<br>3/5 and 1%<br>and​
dybincka [34]

Answer:

3/500

Step-by-step explanation:

3/5 x 1%

=> 3/5 x 1/100

=> 3/500

Hope it helps you

8 0
3 years ago
Which of the following is an integer?<br> 0.5<br> 1<br> 3/2
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Yeah the answer is one
3 0
2 years ago
Read 2 more answers
What is 3 and 7 tens plus 8 and 2 fifth
vladimir2022 [97]
If you are trying to get the answer to
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Your answer would be a mixed number.
<span>4</span>\frac{3}{7}
8 0
2 years ago
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