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pentagon [3]
2 years ago
8

Dr. Ellison says that the equation y = 17x + 1 has a solution of (1,18).

Mathematics
2 answers:
nekit [7.7K]2 years ago
7 0

The solution of an equation is the true value of the equation.

The true statement is <em>(a) Dr. Ellison is right</em>

<em />

The equation is given as:

\mathbf{y =17x + 1}

The solution is given as: (1,18)

Substitute 1 for x and 18 for y.

So, we have:

\mathbf{18 =17 \times 1 + 1}

Multiply

\mathbf{18 =17 + 1}

Add

\mathbf{18 =18}

The above equation is true.

Hence, the true statement is (a) Dr. Ellison is right

Read more about equations at:

brainly.com/question/545403

viva [34]2 years ago
4 0

By considering the point (1,18) as Dr. Elisson's solution. Choice A: Dr. Ellison is right.

According to the question;

  • We are required to determine if Dr. Ellison is right or wrong.

By substituting 1 and 18 for x and y in the equation; we have;

  • 18 = 17(1) + 1

  • 18 = 18

In essence, Dr. Ellison is right.

Read more;

brainly.com/question/2159099

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M∠E ≅ m∠J
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So, m∠ L is 58.
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Trying to help my bro solve this <br>Y= -2x+2
Alexus [3.1K]
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Express the function graphed on the axes below as a piecewise function.
adoni [48]

Answer:

  f(x) = {x-3 for x ≤ -1; -3x+14 for x > 5}

Step-by-step explanation:

To write the piecewise function, we can consider the pieces one at a time. For each, we need to define the domain, and the functional relation.

__

<h3>Left Piece</h3>

The domain is the horizontal extent. It is shown as -∞ to -1, with -1 included.

The relation has a slope (rise/run) of +1, and would intersect the y-axis at -3 if it were extended.

The first piece can be written ...

  f(x) = x-3 for x ≤ -1

__

<h3>Right Piece</h3>

The domain is shown as 5 to ∞, with 5<em> not included</em>.

The relation is shown as having a slope (rise/run) of (-3)/(1) = -3. If extended, it would intersect the point (5, -1), so we can write the point-slope equation as ...

  y -(-1) = -3(x -5)

  y = -3x +15 -1 = -3x +14

The second piece can be written ...

  f(x) = -3x +14 for x > 5

__

<h3>Whole function</h3>

Putting these pieces together, we have ...

  \boxed{f(x)=\begin{cases}x-3&\text{for }x\le-1\\-3x+14&\text{for }5 < x\end{cases}}

_____

<em>Additional comment</em>

Sometimes it is convenient to write inequalities in number-line order (using < or ≤ symbols). This gives a visual indication of where the variable stands in relation to the limit(s). Perhaps a more conventional way to write the domain for the second piece is, <em>x > 5</em>.

3 0
2 years ago
1. Find the Least Common Multiple of these two monomials:<br> See picture
gtnhenbr [62]

Answer:

<em>The last choice is correct</em>

<em />LCM=120a^4b^7c^5<em />

Step-by-step explanation:

<u>Least Common Multiple (LCM)</u>

To find the LCM we can follow this procedure:

List the prime factors of each monomial.

Multiply each factor the greatest number of times it occurs in either factor.

We have two monomials:

12a^4b^2c^5

40a^3b^7c^1

The prime factors of the first monomial are:

2^2,3,a^4,b^2,c^5

The prime factors of the second monomial are:

2^3,5,a^3b^7c^1

LCM = Multiply 2^3*3*5*a^4*b^7*c^5

These are all the factors the greatest number of times they occur.

Operating:

LCM=8*15*a^4*b^7*c^5

\boxed{LCM=120a^4b^7c^5}

The last choice is correct

3 0
3 years ago
PLZ HELP The function shown models the total number of insects in a colony x months after a small number of the insects are brou
Zina [86]

Answer:

Ask your teacher

Step-by-step explanation:

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2 years ago
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