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3 years ago

11

The hexagon PQRSTU is plotted on a coordinate plane with vertices P(–1, 0), Q(–1, 3), R(1, 4), S(2, 5), T(4, 4), and U(4, 0). Wh

at is the hexagon's perimeter?

2 answers:

Dominik [7]3 years ago

6 0

Answer:

I got- 18.2

Step-by-step explanation:

I have this on a exam im working on right now.

mamaluj [8]3 years ago

4 0

Answer:

21 sq unit :3

Step-by-step explanation:

(this is what I got)

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Booker has 4 packs of trading cards. There are 12 cards in each pack.<br> is this divison

Murljashka [212]

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3 years ago

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Which figure contains an angle bisector?

Anastaziya [24]

Answer: Figure 2.

Step-by-step explanation:

Suppose that we have an angle with measure ∠M, a bisector would be a line that divides this angle in two equal parts, such that each new angle has measures (∠M)/2

Then the correct option will be the one that has two equal angles.

In figure 2, we can see that RP divides the angle SRQ in two angles 52°, then RP is the bisector of the angle.

Then the correct option is figure 2.

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3 years ago

Explain how you could use a number line to show that -4 + 3 and 3 + (-4) have the same value

iogann1982 [59]

Find (-4) on the number line and move 3 to the right. You will end up at (-1).

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3 years ago

Greta is trying to determine the portion of green candies in various bags of green and yellow candies. Using the information bel

IrinaK [193]

Answer: a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

Step-by-step explanation:

Since we have given that

There are green and yellow candies in each bag.

Bag A: Two thirds of the candies are yellow. What portion of the candies is green?

Part of yellow candies in bag A = $\dfrac{2}{3}$

Part of green candies in bag A would be

$1-\dfrac{2}{3}\\\\=\dfrac{3-2}{3}\\\\=\dfrac{1}{3}$

Bag B: 29 % of the candies are yellow. What portion of the candies is green?

Percentage of candies are yellow = 29%

Portion of candies are green is given by

$1-\dfrac{29}{100}\\\\=1-0.29\\\\=0.71\\\\=\dfrac{71}{100}$

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Portion of yellow candies = $\dfrac{4}{9}$

Portion of green candies would be

$1-\dfrac{4}{9}\\\\=\dfrac{9-4}{9}\\\\=\dfrac{5}{9}$

Hence, a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

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3 years ago

A. g(x)=3x^2<br> b. g(x)=(1/9x)^2<br> c. g(x)-1/3x^2<br> d. g(x)(1/3x)2

zaharov [31]

Answer:

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