Answer:
Step-by-step explanation:
Assuming Roberto wants to completely fill each page that he puts cards in, this function describes the number of 2-card pages, a, and 3-card pages, b.
2a + 3b =18
Ricardo can fill up 9 2-card pages, and 6 3-card pages.
a=9, b=0
We must add 2 3-card pages at a time,so that we have an even number for the 2-card pages:
a=6, b=2
Add 2 to b once more:
a=3, b=4
One more time:
a=0, b=6:
Thus, Ricardo can display his figures in the following page combinations:
a=9, b=0
a=6, b=2
a=3, b=4
a=0, b=6
Remember that a= number of 2-card pages and b=number of 3-card pages
There are 4 different ways that Ricardo can arrange his figures in terms of what kind of pages he uses.
Answer:
Hundredths place
Step-by-step explanation:
6 in 6.54 is ones place
5 in 6.54 is tenths place
4 in 6.54 is hundredths
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Answer:
49N
Step-by-step explanation:
Step one
Given
When the force of 63 N acts on a certain object
the acceleration of the object is 9/ms^2
Firstly, we need to calculate the mass m
F=ma-------1
m= F/a
m= 63/9
m= 7kg
Step two:
Also, if the acceleration of the object becomes 7 m/s^2
then the force
Note: the mass remains the same= 7kg
F=ma
F=7*7
F= 49N
The answer is in the picture! I hope this helps!
Answer:
x would be equal to 70 grades
Step-by-step explanation:
The angle QRS is equal to 180 - 130 = 50 grades.
We add up that with the other 60 grades on the left, and we encounter ourselves with a simple equation:
60 + x + 50 = 180
x = 70
Hope this was helpful