Answer:

Explanation:
The strength of the gravitational field at the surface of a planet is given by
(1)
where
G is the gravitational constant
M is the mass of the planet
R is the radius of the planet
For the Earth:

For the unknown planet,

Substituting into the eq.(1), we find the gravitational acceleration of planet X relative to that of the Earth:

And substituting g = 9.8 m/s^2,

Answer:
a) Resistivity=R.A/L
Here, R=500000ohm, L=1.6m, A=2pi* (0.14/2)*0.002 m2=0.00088.........we have converted quantities into SI units
Resistivity=R.A/L
=500000*0.00088/1.6 = 440/1.6= 275 ohm.meter
b) pskin/pinterior =275/4.8=57.3
For second part, correct option is (A), because cross section area is smaller.
The lowest possible temperature is absolute zero. However scientists have not reached this temperature, rather they have come very close to absolute zero.
Answer:
At the lowest point in the oscillation, the momentum is zero.
At the lowest point in the oscillation, 
Explanation:
Since spring block system is performing to and fro motion along straight line
So here we can say at the lowest position of its path the velocity will become zero.
So we can say that momentum of the spring block system is given as


Also we know that after reaching the lowest point the block will again go up towards its mean position
So at the lowest point of the spring block system the block will move upwards again
So this will accelerate upwards hence

