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4 years ago

NEED HELP

Physics

2 answers:

zlopas [31]4 years ago

4 0

there it is fella tried on ma own consciousness

fomenos4 years ago

3 0

Answer:

33.8

Explanation:

(Acellus)

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A geneticist looks through a microscope to determine the phenotype of a fruit fly. The microscope is set to an overall magnifica

grin007 [14]

Answer:

$f_e = 1.51 cm$

Explanation:

given.

magnification(m) = 400 x

focal length (f_0)= 0.6 cm

distance between eyepiece and lens (L)= 16 cm

Near point (N) = 25 cm

focal length of the eyepiece (f_e)= ?

using equation

$m = -\dfrac{L-f_e}{f_o}.\dfrac{N}{f_e}$

$400 = \dfrac{16-f_e}{0.6}.\dfrac{25}{f_e}$

$9.6 = \dfrac{16-f_e}{f_e}$

$9.6f_e = 16-f_e$

$10.6 f_e = 16$

$f_e = 1.51 cm$

3 0

4 years ago

In a given chemical reaction, the energy of the products is kess than the energy of the reactants. Which statement is true for t

deff fn [24]

Answer: Released

Explanation: Energy is released in this reaction possibly in the form of heat thus it is an exergonic and or exothermic reaction.

5 0

3 years ago

Which of the following is an example of light energy being changed to chemical energy?

gtnhenbr [62]

Answer:

A solar panel

Explanation:

7 0

3 years ago

A 55.0 kg bungee jumper steps off a bridge with a light bungee cord tied to her and to the bridge. The unstretched length of the

lianna [129]

Answer:

$69.06\ \text{N/m}$

Explanation:

m = Mass of bungee jumper = 55 kg

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

h = Height at the bottom = 40 m

k = Spring constant

x = Displacement of bungee cord = 25 m

Applying the principle of conservation of energy to the system we have

$mgh=\dfrac{1}{2}kx^2\\\Rightarrow k=\dfrac{2mgh}{x^2}\\\Rightarrow k=\dfrac{2\times 55\times 9.81\times 40}{25^2}\\\Rightarrow k=69.06\ \text{N/m}$

The spring constant of the bungee cord is $69.06\ \text{N/m}$ .

5 0

3 years ago

The lowest note on a grand piano has a frequency of 27.5 Hz. The entire string is 2.00 m long and has a mass of 400 g. The vibra

Norma-Jean [14]

Answer:

1456 N

Explanation:

Given that

Frequency of the piano, f = 27.5 Hz

Entire length of the string, l = 2 m

Mass of the piano, m = 400 g

Length of the vibrating section of the string, L = 1.9 m

Tension needed, T = ?

The formula for the tension is represented as

T = 4mL²f²/ l, where

T = tension

m = mass

L = length of vibrating part

F = frequency

l = length of the whole part

If we substitute and apply the values we have Fri. The question, we would have

T = (4 * 0.4 * 1.9² * 27.5²) / 2

T = 4368.1 / 2

T = 1456 N

Thus, we could conclude that the tension needed to tune the string properly is 1456 N

4 0

3 years ago