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Nezavi [6.7K]
3 years ago
7

I am unique even though there are billions of me no two are the same what am I

Physics
2 answers:
Aleksandr [31]3 years ago
6 0
I think the answer is Snow flakes
erastova [34]3 years ago
4 0

Answer:

Flowers

Explanation:

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The track of a roller coaster is shown below. At which point will the riders experience centripetal acceleration?
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Centripetal acceleration is applied in circular motion. Y is the point on the track that most closely resembles a circular path for the roller coaster.

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4. A cell membrane contains all of the following EXCEPT:*
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Answer:

The correct answer is - none of the above.

Explanation:

Cell membranes or plasma membranes of the cell are composed mainly of fatty-acid-based lipids and proteins. Membrane lipids are of two types majorly, glucolipids, phospholipids, and sterols (generally cholesterol).

Sphingolipids are also a structural component of the cell membrane that helps in segregation into distinct membrane domains. Glycolipids are present on the surface of the plasma membrane.

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A car goes from 40n/s to 60 m/s in 8s the acceleration of the car is
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Acceleration= change in velocity/ change in time.

60-40=20 m/s (change in speed)
Time= 8 seconds

20/8= 2.5
Acceleration= 2.5 m/s^2

Hope this helps! :)
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3 years ago
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Explain what is required for destructive interference in an air wedge.
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Solve the following quadratic equations:2x² - 4x - 9 = 0 x₊ = 1 + √22/2Answersx_ = 1 - √22/2
Pavel [41]

The root quadratic equation of 2x^{2}  - 4x - 9 = 0 is x=\frac{2+\sqrt{22}}{2},\:x=\frac{2-\sqrt{22}}{2}

What is the formula used to calculate the quadratic equation?

To solve the quadratic equation use the formula of x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Find the quadratic equation by using the formula ?

On comparing with 2x^{2}  - 4x - 9 = 0

We get , a=2 , b=-4 , c=-9

D=b^{2} +7\\\\\\=(-4)^{2} +7*2*(-9)\\\\=-16-126\\\\=110

By using the formula,

For a quadratic equation of the formax^2+bx+c=0 the solutions are

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

X==\frac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\c* \:2\left(-9\right)}}{2\c* \:2}\\\\\sqrt{\left(-4\right)^2-4\cdot \:2\left(-9\right)}\\\\

Apply rule,

-(-a)=a\\\\=\sqrt{\left(-4\right)^2+4\cdot \:2\cdot \:9}\\\\

Apply exponent rule,

(-a)^{n} =a^{n} if n is even

(-4)^{2} =4^{2}

\sqrt{4^2+4\cdot \:2\cdot \:9}

Multiply the numbers :

4*2*9=72\\\\\sqrt{4^2+4\cdot \:2\cdot \:9}\\\\4^{2} =16\\\\=\sqrt{16+72}\\\\

Add the number  =\sqrt{88}

6 0
2 years ago
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