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2 years ago

13

how is it that an electric bulb lights up as soon as we turn the switch on if the drift speed is 1mm /s^2

1 answer:

galben [10]2 years ago

5 0

Two analogies:
1. The wires are like hoses full of water. As soon as you turn on the water, water is pushed out the end of the hose.
2. Although the electrons only move at 1mm/s, the electomagnetic pulse travels through the circuit at near speed of light (varies btw .1c to .9c). It is this pulse that provides the pressure to push the electrons out the end of the wire into the light

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What does the column that an element is in tell you?

Mumz [18]

Answer:

The column number tells us the amount of valence electron the element has

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2 years ago

A metal wire is in thermal contact with two heat reservoirs at both of its ends. Reservoir 1 is at a temperature of 781 K, and r

andreev551 [17]

Answer:2.517 J/K

Explanation:

Given

Reservoir 1 Temperature $T_1=781 K$

Reservoir 2 Temperature $T_2=335 K$

Let Q is the amount of heat Flows i.e. $Q=1477 J$

thus change in Entropy is given by $\frac{\sum Q}{T}$

$\Delta S=\frac{\sum Q}{T}=-\frac{Q}{T_1}+\frac{Q}{T_2}$

$\Delta S=\frac{\sum Q}{T}=-\frac{1477}{781}+\frac{1477}{335}$

$\Delta S=\frac{\sum Q}{T}=-1.891+4.4089$

$\Delta S=\frac{\sum Q}{T}=2.517 J/K$

6 0

2 years ago

What techniques allow us to identify the presence of different elements?

boyakko [2]

Answer:

c

Explanation:

4 0

2 years ago

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A force of 120 N is applied to the front of a sled so as to pull the sled a distance of 165

Marrrta [24]

Answer:

<h3>The answer is 19,800 J</h3>

Explanation:

The work done by an object can be found by using the formula

<h3>workdone = force × distance</h3>

From the question

force = 120 N

distance = 165 m

We have

work done = 120 × 165

We have the final answer as

<h3>19,800 J</h3>

Hope this helps you

8 0

3 years ago

In introductory physics laboratories, a typical Cavendish balance for measuring the gravitational constant G uses lead spheres w

NeTakaya

Answer:

F=2.47*10^{-10} N

Explanation:

The gravitational force is calculated by using

$F=G\frac{M_1M_2}{r^2}$

G: Cavendish constant = 6.67*10^{-12}Nm^2/kg^2

r=2.30cm=0.023m

M1=1.4kg

M2=14.0g=0.014kg

By replacing we have

F=2.47*10^{-10} N

hope this helps!!

6 0

2 years ago

Read 2 more answers