To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
1680
Step-by-step explanation:
280 x 6 = 1680
Answer:
I think thr answer mughr ve B for what it sais
220.5
i dont know how to show my work sorry :) hope it helps
Divide 12 by 72. this equals 6. then multiply. 7x6=47 3x6=18 and 5x6=30 there we go!
