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oksian1 [2.3K]
3 years ago
8

When the denominator and numerator are equal, it means?

Mathematics
1 answer:
WITCHER [35]3 years ago
5 0
The fraction is one whole aka one
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In the circle shown, AB is tangent to circle o at point and OC is a radius
Vlada [557]

Answer:

A. \overline{OC} \perp \overline{AB}

Step-by-step explanation:

According to tangent theorem, a tangent is formed when the radius of a circle is perpendicular to the line, meeting at a point around the circle, such that the tangent line would be perpendicular to the radius of the circle with a center.

Given that \overline{AB} is a tangent of the circle O, at a point C, and \overline{OC} is a radius, therefore, it follows that:

\overline{OC} \perp \overline{AB}.

This means the radius of the circle is perpendicular to the tangent formed at point C.

8 0
3 years ago
A bike rental company charges $60 for the first hour, and $25 for each additional hour. Michael wants to spend less than $200 on
-Dominant- [34]
It is d. The h is the amount of hours and this must be paired with 25 because that is the rate do you can eliminate b and c. It is not a because that is making it so the cost is above 200 when you are trying to keep it below that
4 0
3 years ago
Read 2 more answers
Estimate the sum 258+565
Thepotemich [5.8K]
So do 260+570 which is 830

The real sum is 823
7 0
3 years ago
what is f(x) = 2x2 28x – 5 written in vertex form? f(x) = 2(x 7)2 – 19 f(x) = 2(x 7)2 – 103 f(x) = 2(x 14)2 – 14 f(x) = 2(x 14)2
Katarina [22]
Hello,
++++++++++++++++++++++
Answer B
++++++++++++++++++++++

2x²+28x-5=2(x²+2*7x+49)-5-2*48
=2(x+7)²-103

++++++++++++++++++++++++++++++
4 0
4 years ago
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A regular triangular pyramid has a base area of 31.5 mm2 and a surface area of
Virty [35]

Answer:

A) 220.5 mm^2

Step-by-step explanation:

<u>Explanation</u>:-

Given A regular triangular pyramid has a base of area is 31.5mm^2

and also given surface area of triangular pyramid is 252 mm ^2

by using formula

surface area of  regular triangular pyramid = base of area + half of lateral surface.

surface area = area of the pyramid X \frac{1}{2} lateral surface

252 = 31.5 + \frac{1}{2} lateral surface

252-31.5= \frac{1}{2} lateral surface

220.5 = lateral area of triangular pyramid

lateral area of triangular pyramid = 220.5 mm^2

6 0
4 years ago
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