We'd need a value, a coefficient, that effectively tosses away the variable "y" and leaves "x" all by her lonesome.
and our sharpest value for that, is our very good friend Mr Zero, c = 0, cy = 0y = 0.
check the picture below.
Answer:
Step-by-step explanation:
<em>See above image</em>
I am joyous to assist you at any time.
6787.100 would be your answer.
3(2t+5)=5t+25
Multiply the bracket with 3
(3)(2t)(3)(5)=5t+25
6t+15=5t+25
Move 5t to the other side. Sign changes from +5t to -5t
6t-5t+15=5t-5t+25
6t-5t+15=25
Move +15 to the other side. Sign changes from +15 to -15
6t-5t+15-15=25-15
6t-5t=10
1t=10
divide by 1
1/1t=10/t
t=10
Answer: t=10
I'm gonna go ahead and assume you're asking me to solve ((2x+1)(3x-2))/(24x^2-4x-8).
((2x+1)(3x-2))/(24x^2-4x-8)
1. Factor out the common term 4.
((2x+1)(3x-2))/(4(6x^2-x-2))
2. Split the second term in 6x^2-x-2 into two terms.
((2x+1)(3x-2))/(4(6x+3x-4x-2))
3. Factor out common terms in the first two terms, then in the last two terms.
((2x+1)(3x-2))/(4(3x(2x+1)-2(2x+1)))
4. Factor out the common term 2x+1
((2x+1)(3x-2))/(4(2x+1)(3x-2))
5. Cancel 3x-2
1/4
The answer to your question is 1/4.