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3 years ago

What elements are pliable??

Chemistry

1 answer:

horrorfan [7]3 years ago

6 0

Answer:

Yttrium, Silver,Iron,Nickel and Copper I believe

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The student is now told that the four solids, in no particular order, are calcium bromide (CaBr2), sugar (C6H12O6), benzoic acid

lara [203]

MgBr2, 3 ions per mole=best conductor

KBr, 2 ions per mole, 2nd best conductor

Benzoic acid, weak acid, slightly ionized, weak conductor

Sugar, molecular, non ionized, non conductor

8 0

3 years ago

The second-order rate constant for the following gas-phase reaction is 0.041 1/MLaTeX: \cdotâs. We start with 0.438 mol C2F4 in

pantera1 [17]

Answer:

134.8 seconds is the half-life (in seconds) of the reaction for the initial $C_2F_4$ concentration

Explanation:

Half life for second order kinetics is given by:

$t_{\frac{1}{2}=\frac{1}{k\times a_0}$

Integrated rate law for second order kinetics is given by:

$\frac{1}{a}=kt+\frac{1}{a_0}$

$t_{\frac{1}{2}$ = half life

k = rate constant

$a_0$ = initial concentration

a = Final concentration of reactant after time t

We have :

$C_2F_4 \longrightarrow \frac{1}{2} C_4F_8$

Initial concentration of $C_2F_4=[a_o]=\frac{0.438 mol}{2.42 L}=0.1810 mol/L$

Rate constant = k = $0.041 M^{-1} s^{-1}$

$t_{\frac{1}{2}=\frac{1}{k\times a_0}$

$=\frac{1}{0.041 M^{-1} s^{-1}\times 0.1810 mol/L}$

$t_{1/2}=134.8 s$

134.8 seconds is the half-life (in seconds) of the reaction for the initial $C_2F_4$ concentration

3 0

3 years ago

Describe the patterns that can be observed for elements on a Periodic table.

pishuonlain [190]

Answer:

mark brainliestbrainliestbrainliest.

Explanation:

The periodic table is an arrangement of the elements in order of increasing atomic number. Elements that exhibit similar chemistry appear in vertical columns called groups (numbered 1–18 from left to right); the seven horizontal rows are called periods.

7 0

2 years ago

Na + Cl --> NaCl

dalvyx [7]

Answer:

38.152 g NaCl would be produced.

Explanation:

$\frac{(23 + 35.5) \times 15}{23} \\ = 38.152 \: \: g$

Mark me as Brainliest 

5 0

3 years ago

Read 2 more answers

Which product(s) would be obtained by the dehydration of 2-heptanol? of 2-methyl-l-cyclohexanol?

Komok [63]

Hello)
1)CH3-CH(OH)-СН2-СН2-СН2-СН2-СН3---(H2SO4)--›CH3-CH=CH-CH2-CH2-CH2-CH3+H2O
2)2-methyl-l-cyclohexanol---(h2so4)--›CH2=C(CH3)-CH2-CH2-CH2-CH2-CH3+H2O

5 0

3 years ago