the answer is d thats what i think
The wall pushes back with the same force you exert so 40N.
to show your acceleration is .5m/s^2 use newtons second law F=ma
so plugging in numbers gives 40N=80kg*a knowing that a newton is equal 1kgm/s^2 we could write 40kg*m/s^2= 80kg*a so solving for a gives
40kg*m/s^2/80kg = a we see the kg's cancel and we're left with
(40m/s^2)/80=a which gives .5m/s^2=a
Answer:
Increase
Explanation:
If we assume the gas is ideal, then we can use the ideal gas law:
PV = nRT
If V is held constant while P increases, then T will also increase.
Answer:
0.08 ft/min
Explanation:
To get the speed at witch the water raising at a given point we need to know the area it needs to fill at that point in the trough (the longitudinal section), which is given by the height at that point.
So we need to get the lenght of the sides for a height of 1 foot. Given the geometry of the trough, one side is the depth <em>d</em> and the other (lets call it <em>l</em>) is given by:
since the difference between the upper and lower base is the increase in the base and we are only at halft the height.
Now we can calculate the longitudinal section <em>A</em> at that point:
And the raising speed <em>v </em>of the water is given by:
where <em>q</em> is the water flow (1 cubic foot per minute).
The force the cannonball is exerting on the moon, or the weight of the cannonball, is 32 Newtons because the formula used to calculate force is
, the Mass being 20 Kilograms and the Acceleration being 1.6 meters per second^2