Complete question :
NASA is concerned about the ability of a future lunar outpost to store the supplies necessary to support the astronauts. The supply storage area of the lunar outpost, where gravity is 1.63 m/s2, can only support 1 x 10^5 N. What is the maximum WEIGHT of supplies, as measured on EARTH, NASA should plan on sending to the lunar outpost
Answer:
601,220N
Explanation:
Given that:
Gravity at lunar outpost = 1.63m/s²
Acceleration due to gravity on earth = 9.8m/s²
Supported weight = 1 * 10^5 N
Maximum weight of supplies as measured on earth;
(Ratio of the gravities) * weight of supplies
(9.8m/s² / 1.63m/s²) * (1 * 10^5 N)
6.0122 * (1 * 10^5)
6.0122 * 10^5 N
= 601,220 N
-3.33 m/s^2
The soccer player decelerates from 10 m/s
to 0 m/s. Because he decelerates the acceleration will be a negative
value. Since he takes 3 seconds to decelerate, divide his original
velocity by 3
One major point to be careful of is to keep p
Answer:
The car must move at 2 m/s to have a Ke of 2,000 Joules.
Explanation:
Mark me pls
Answer:

Explanation:
The incident angle is
so the reflected ray will also be
.
The normal divides the angle between the incident and reflected ray. So, the angle between them would be

So, the angle between the incident and reflected rays is
.
Choice D). is on the right track, but it's stated incorrectly.
The wavelengths of light coming from a galaxy that's moving toward us <em>are </em>
<em>shorter</em> than they were when they left the galaxy. When we see them, they're
shorter than they should be.
(This is called a "blue shift" in the spectrum of the galaxy, because blue is the
short-wavelength end of the spectrum of visible light. If the wavelength of some
light somehow becomes shorter, then the color of the light changes toward the
direction of blue.)
If the source of light is moving toward us, then the wavelength we see is shorter
than it should be. If the source is moving away from us, then the wavelength
we see is longer than it should be. The whole trick to this is knowing <u>what</u> the
wavelength of the light we see <em>should be</em> !