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valina [46]
3 years ago
10

The ocean’s tides are not only affected by the shape of the coastlines, or slope of the ocean floor, but also by the gravitation

al tug of the Sun and the Moon. Write a 600 word report on the effect of the Moon, and Sun, on tidal reaction, and high tides and low tides. What orientation are the Sun and Moon in to create high tides? Low tides? There are two special types of tides. What are they called and what positions are the Sun and the Moon in during these times?
Physics
2 answers:
Genrish500 [490]3 years ago
5 0

Answer:a

Explanation:

dexar [7]3 years ago
4 0

Answer:

a) According to Newton's law of gravitation, as the distance between the Moon and the Earth decreases, the gravitational attraction increases and vice versa

The gravitational force of the Moon on the Earth causes the Earth to be slightly bulged on the side directly facing the Moon

The gravitational force also pulls the water bodies on the Earth's surface towards the Moon in the same manner and the effect is more pronounced due to the ability of the liquid water to assume a shape based on the magnitude of the gravitational field attracting it

Therefore, the region where the Moon is closest to the Earth we have a high tide as the water level rises and the region which is perpendicular to where the Moon is located has a  low tide

b) The two special types of tides are

1) The neap tide

2) The spring tide

Neap tide

Neap tide occurs when the Sun and Moon are 90° apart from each other when they are viewed by an observer from Earth

The gravitational pull of the Sun cancels (partially) the effect of the gravitational pull and tidal force of the Moon, resulting in minimum tidal range

Spring Tide

Spring tide occurs when the Earth, the Moon, and the Sun are simultaneously inline, such that the Sun reinforces the gravitational pull and tidal force of the Moon, resulting in a maximum tidal range

Explanation:

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Analyzing a blood sample usually involves which type of separation method?
schepotkina [342]

Answer:(D.)

Explanation:

4 0
3 years ago
A flywheel turns through 40 rev as it slows from an angular speed of 1.5 rad/s to a stop.
Lynna [10]

Answer:

-0.0047 rad/s²

335.103 seconds

99.18 seconds

Explanation:

\omega_f = Final angular velocity

\omega_i = Initial angular velocity = 1.5 ra/s

\alpha = Angular acceleration

\theta = Angle of rotation = 40 rev

t = Time taken

Equation of rotational motion

\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}\\\Rightarrow \alpha=\frac{0^2-1.5^2}{2\times 2\pi \times 40}\\\Rightarrow \alpha=-0.0047\ rad/s^2

Acceleration while slowing down is -0.0047 rad/s²

t=\frac{\omega_f-\omega_i}{\alpha}\\\Rightarrow t=\frac{0-1.5}{-0.0047}\\\Rightarrow t=335.103\ s

Time taken to slow down is 335.103 seconds

\theta=\omega_it+\frac{1}{2}\alpha t^2\\\Rightarrow 20\times 2\pi=1.5\times t+\frac{1}{2}\times -0.0047\times t^2\\\Rightarrow 0.00235t^2-1.5t+125.66=0

Solving the equation

t=\frac{-\left(-1.5\right)+\sqrt{\left(-1.5\right)^2-4\cdot \:0.00235\cdot \:125.66}}{2\cdot \:0.00235}, \frac{-\left(-1.5\right)-\sqrt{\left(-1.5\right)^2-4\cdot \:0.00235\cdot \:125.66}}{2\cdot \:0.00235}\\\Rightarrow t=539.11, 99.18\ s

The time required for it to complete the first 20 is 99.18 seconds as 539.11>335.103

4 0
3 years ago
A copper wire of length 16 cm is in a magnetic field of 0.19 T. If it has a mass of 9.0 g, what is the minimum current through t
Sergeeva-Olga [200]

Answer:

2.9 A

Explanation:

L = 16 cm = 0.16 m

B = 0.19 T

m = 9 g = 0.009 kg

Let the minimum current be i.

Magnetic force is balanced by the gravitational force

B x i x L = m x g

0.19 x i x 0.16 = 0.009 x 9.8

i = 2.9 A

7 0
3 years ago
A solenoid of radius r 5 1.25 cm and length , 5 30.0 cm has 300 turns and carries 12.0 A. (a) Calculate the flux through the sur
Elina [12.6K]

Answer:

\phi = 7.4 \times 10^{-6} Wb

Explanation:

Magnetic field due to a long solenoid at the center is given by

B = \frac{\mu_o N i}{L}

here we know that

N = 300

L = 30 cm

i = 12 A

now magnetic field is given as

B = \frac{(4\pi \times 10^{-7})(300)(12)}{0.30}

B = 0.015 T

Now magnetic flux through the disc is given as

\phi = B.A

\phi = (0.015)(\pi r^2)

\phi = (0.015)(\pi)(0.0125)^2

\phi = 7.4 \times 10^{-6} Wb

8 0
3 years ago
Wood has chemical energy which can be used to generate thermal and radiant energy when burned in a fire place which best explain
creativ13 [48]

Answer:

the answer is b:D

Explanation:

5 0
2 years ago
Read 2 more answers
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