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3 years ago

You have 150 W/m^2 hitting your roof each day. You can convert 13% of it into

Physics

1 answer:

damaskus [11]3 years ago

3 0

Answer:

Energy = .13 W / m^2 energy of incident energy

N = 3500 Watts / day power needed

N = 3500 Watts (3600 * 24 sec) = .0405 Watts/sec

The problem must mean that one needs 3.5 Kw-days

3.5 Kw-days = 3500 watts * 86400 sec = 3.02E8 joules

150 J/sec-m^2 * .13 = 19.5 J / sec-m^2 usable energy

In one day 19.5 J/sec-m^2 = 1.68E6 J/m^2 usable energy received

Area = 3.028E8 J / 1.68E6 J/m2 = 180 m^2

One would need 180 m^2 of solar panels

That's quite a lot of energy

A 1100 watt microwave oven uses 1.1 kW while running so 3.5 kW for 24 hours seems to be quite a lot.

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. A student claims that if lighting strikes a metal flagpole, the force exerted by the Earth’s magnetic field on the current in

Ratling [72]

Answer:

Explanation:

Given that, current generated from lightning range from

10⁴ A < I < 10^5 A

We know that,

The magnetic force is given as

F = iLB

The magnetic field on the earth surface is

B = 10^-5 T

So, let assume the worst case of a 15m flag pole

L = 15m

Then,

F = iLB

F = 10^5 × 10 × 10^-5

F = 15 N

Therefore, 15N is fairly strong so it will come to the material that was use for the material of the flag pole.

Therefore, it is possible that the student is right depending on the material of the flag pole.

7 0

4 years ago

How much force is required to accelerate a 2kg mass at 3 m/s2? answer key?

mr Goodwill [35]

F = ma so u can plug in the given numbers and solve:

F = (2)(3)

4 0

3 years ago

As a stands, her entire weight is momentarily placed on the heels of her high-heeled shoes. Calculate the pressure exerted on th

Lena [83]

Answer:

Pressure will be $6072449.952Pa$

Explanation:

We have given mass of the women m = 65 kg

Radius of the heels r = 0.578 cm = 0.00578 m

We have to find the pressure

We know that pressure is given by

$P=\frac{F}{A}=\frac{mg}{A}$

So force F = mg = 65×9.8 = 637 N

Area $A=\pi r^2=3.14\times 0.00578^2=1.049\times 10^{-4}m^2$

So pressure $p=\frac{637}{1.049\times 10^{-4}}=6072449.952Pa$

5 0

4 years ago

A cylinder of gas is at room temperature (20°C). The air conditioner breaks down, and the temperature rises

noname [10]

Answer: we divide this equation by pV and use {C}_{p}={C}_{V}+ . ... The temperature, pressure, and volume of the resulting gas-air mixture

Explanation:

4 0

3 years ago

A 290 gg bird flying along at 6.2 m/sm/s sees a 9.0 gg insect heading straight toward it with a speed of 34 m/sm/s (as measured

Murrr4er [49]

Answer:

The bird's speed immediately after swallowing is 4.98 m/s.

Explanation:

Given that,

Mass of bird = 290 g

Speed = 6.2 m/s

Mass of sees = 9.0 g

Speed = 34 m/s

We need to calculate the bird's speed immediately after swallowing

Using conservation of momentum

$m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})v_{3}$

Put the value into the formula

$0.290\times6.2+0.009\times(-34)=(0.290+0.009)\times v_{3}$

$v_{3}=\dfrac{0.290\times6.2-0.009\times34}{(0.290+0.009)}$

$v_{3}=4.98\ m/s$

Hence, The bird's speed immediately after swallowing is 4.98 m/s.

6 0

3 years ago