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3 years ago

You have 150 W/m^2 hitting your roof each day. You can convert 13% of it into

Physics

1 answer:

damaskus [11]3 years ago

3 0

Answer:

Energy = .13 W / m^2 energy of incident energy

N = 3500 Watts / day power needed

N = 3500 Watts (3600 * 24 sec) = .0405 Watts/sec

The problem must mean that one needs 3.5 Kw-days

3.5 Kw-days = 3500 watts * 86400 sec = 3.02E8 joules

150 J/sec-m^2 * .13 = 19.5 J / sec-m^2 usable energy

In one day 19.5 J/sec-m^2 = 1.68E6 J/m^2 usable energy received

Area = 3.028E8 J / 1.68E6 J/m2 = 180 m^2

One would need 180 m^2 of solar panels

That's quite a lot of energy

A 1100 watt microwave oven uses 1.1 kW while running so 3.5 kW for 24 hours seems to be quite a lot.

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which of the following statements is not true Negatively charged objects attract other negatively charged objects. Positively ch

maxonik [38]

Answer:

negatively charged object attract other negatively objects

Explanation:

opposites attract

3 0

4 years ago

Read 2 more answers

The inner and outer surfaces of a cell membrane carry a negative and positive charge, respectively. Because of these charges, a

sertanlavr [38]

Answer:

Electric field, E = $6.36\times 10^{6}\ V/m$

Explanation:

Given that,

The potential difference across the membrane, $\Delta V=0.063\ V$

The thickness of the membrane is, $\Delta x=9.9\times 10^{-9}\ m$

We need to find the magnitude of the electric field in the membrane. We know that the relation between electric field and electric potential is given by :

$E=\dfrac{-\Delta V}{\Delta x}\\\\E=\dfrac{0.063\ V}{9.9\times 10^{-9}\ m}\\\\E=6.36\times 10^{6}\ V/m$

So, the magnitude of the electric field in the membrane is $6.36\times 10^{6}\ V/m$ .

7 0

4 years ago

A supersonic aircraft flies at 3 km altitude at a speed of 1000 m/s on a standard day. How long after passing directly above a g

Gre4nikov [31]

Answer:

<h3>After 3seconds</h3>

Explanation:

A supersonic aircraft flies at 3 km altitude at a speed of 1000 m/s on a standard day. How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer

Using the formula for calculating speed expressed as;

Speed = Distance/Time

Given;

Distance = 3km = 3000m

Speed = 1000m/s

Required

How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer (Time)

From the formula;

Time = Distance/speed

Time = 3000/1000

Time = 3seconds

Hence the sound of the aircraft is heard after 3 seconds

7 0

3 years ago

3. Identify which of the following probably would not have an effect on the climate of a region:

Nat2105 [25]

C.) A thunderstorm
That’s the Answer

6 0

3 years ago

If element "X" is heavier than element "Y" then...

Molodets [167]

The best answer would be C.

The mass of an element depends on the number of particles found in the nucleus of the atom. Atomic mass can be computed by adding the number of protons and the number of neutrons. Protons and neutrons are found in the nucleus of an atom. So the answer must be letter C.

3 0

3 years ago