Answer:
Explanation:
ball's weight = mg = .5 x 9.8 = 4.9 N.
If T₁ be tension at the top , centripetal force provided at the top
= mg + T₁ = 4.9 + T₁
4.9 + T₁ = m v² / r , v = velocity at the top , r = radius of circular path = 1.02 m
4.9 + T₁ = .5 x 4² / 1.02
4.9 + T₁ = .5 x 4² / 1.02
= T₁ = 7.843 - 4.9 = 2.943 N
If T₂ be tension at the bottom , centripetal force provided at the bottom
= T₂ - mg = T₂ - 4.9
T₂ - 4.9 = m v² / r , v = velocity at the bottom , r = radius of circular path = 1.02 m
T₂ - 4.9= .5 x 7.5² / 1.02
T₂ - 4.9 = .5 x 7.5² / 1.02
T₂ = 32.47 N
Net force is centripetal force that's inward directions
<span>Uniform circular motion can be described as the motion of an object in a circle at a constant speed. As an object moves in a circle, it is constantly changing its direction. At all instances, the object is moving tangent to the circle. Since the direction of the velocity vector is the same as the direction of the object's motion, the velocity vector is directed tangent to the circle as well. The animation at the right depicts this by means of a vector arrow. </span>
<span>An object moving in a circle is accelerating. Accelerating objects are objects which are changing their velocity - either the speed (i.e., magnitude of the velocity vector) or the direction. An object undergoing uniform circular motion is moving with a constant speed. Nonetheless, it is accelerating due to its change in direction. The direction of the acceleration is inwards. </span>
<span>The final motion characteristic for an object undergoing uniform circular motion is the net force. The net force acting upon such an object is directed towards the center of the circle. The net force is said to be an inward or centripetal force. Without such an inward force, an object would continue in a straight line, never deviating from its direction. Yet, with the inward net force directed perpendicular to the velocity vector, the object is always changing its direction and undergoing an inward acceleration. </span>
<span>The direction is inward therefore the net force is zero. </span>
Answer:
1. They both uses same energy
2. The 6 kg ball requires more power than 3kg ball
Explanation:
Sample 1
m = 3kg
g= 10m/s^2
h = 2m
t = 2secs
W = mgh = 3 x 10 x 2 = 60J
P= w/t = 60/2 = 30watts
Sample 2
m = 6kg
g= 10m/s^2
h = 1m
t = 1sec
W = mgh = 6 x 10 x 1 = 60J
P= w/t = 60/1 = 60watts
They both uses same energy but different power. The 6 kg ball requires more power than 3kg ball
Answer:
it ends when clouds above start to break apart. Some tornadoes only last seconds. Others can last much longer. They come in many shapes and sizes.
Hi there!
We can use the following equation for constant velocity:
d = displacement (m)
v = velocity (m/s)
t = time (s)
Plug in the givens: