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damaskus [11]
4 years ago
10

Andrew kicks a ball along a straight path. The ball rolls straight forward for 13.2 meters. Then Andrew kicks the ball straight

back. The ball rolls back along the same path for 9.5 meters. What distance did the ball travel?
Physics
1 answer:
tresset_1 [31]4 years ago
7 0

Answer: 22.7 meters

Explanation: The distance traveled is how much the ball has rolled in total, this means the lenght of the path that it has followed from begining to end.

Since it first travels 13.2 meters and then 9.5 meters, if we sum this quantities:

13.2 + 9.5 = 22.7 meters

So 22.7 is the distance that the ball has traveled.

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A goose flying south for the winter travels 55 miles directly south east (45 degrees) and then flies at an angle of 35 degrees N
Usimov [2.4K]

Answer:

Part A

The distance from the start point the goose travels is approximately 84.96 miles

Part B

The direction the goose travel is approximately 71° Northeast

Explanation:

Part A

The distances the goose flies is given as follows;

The distance directly 45 degrees southeast the goose travels, AB = 55 miles

The distance Northeast the goose travels, BC = 75 miles

The angle Northeast the goose travels = 35°

From the attached drawing of the path the goose travels, we have, by cosine rule, the following relation;

a² = b² + c² - 2·b·c·cos(A)

Therefore, we have;

The length of side \overline{AC}² = 55² + 75² - 2 × 55 × 75 × cos(80°) = 7217.40253425

\overline{AC} = √(7217.40253425) ≈ 84.9552972701

The distance from the start point the goose travels ≈ 84.96 miles

Part B

By sine rule, we have;

75/(sin(A)) = \overline{AC}/(sin(80°))

sin(A) = (75/\overline{AC}) × (sin(80°)

∴ sin(A) =  (75/84.9552972701) × (sin(80°) = 0.8694052016

∠A = arcsin(0.8694052016) = 60.3895991264° ≈ 60.4°

The direction the goose travel = 180 - 64 - 45 = 71°

∴ The direction the goose travel =≈ 71° Northeast

5 0
3 years ago
What is the speed of a wave with a frequency of 2 Hz and a wavelength of 87 m?​
Deffense [45]

v = λf

v = 87 x 2 = 174 m/s

7 0
3 years ago
If the coefficient of static friction is 0.753, the length of the ladder is 9.9 m, and its mass is 39 kg, find the minimum heigh
anzhelika [568]

The ladder will slip at the point where the reaction at the wall is just over

the force due to friction.

Response:

  • The minimum height below which the ladder will slip, is approximately 5.48 meters above the ground.

<h3>Which method is used to calculate the minimum height before slipping?</h3>

The given parameter are;

The coefficient of friction, μ = 0.753

Length of the ladder = 9.9 m

Mass of the ladder = 39 kg

Required:

The minimum height below which the ladder will slip.

Solution:

Assumption: The friction of the wall on the ladder is 0.

The weight of the ladder, W = The normal reaction = N

The friction force, F_f = The reaction force of the wall, F_w

F_f = W × μ

Which gives;

F_f = 39 × 9.81  × 0.753 ≈ 288.09

The friction force, F_f ≈ 288.09 N = F_w

Taking moments about the contact between the ladder and the ground, we have;

F_w × h = W × x

Where;

h = \mathbf{L \times sin(\theta)}

x = \mathbf{\dfrac{L}{2} \times cos(\theta)}

Which gives;

x = \dfrac{9.9}{2} \times cos(\theta) = \mathbf{4.95 \cdot cos(\theta)}

h = 9.9 \cdot sin(\theta)

θ = The angle made by the ladder and the ground

Therefore;

288.09 × 9.9·sin(θ) =  39 × 9.81 × x  = 382.59 × 4.95·cos(θ)

\dfrac{sin(\theta)}{cos(\theta)} = tan(\theta) =  \dfrac{382.59 \times 4.95}{288.09 \times 9.9}

\theta = arctan \left(\dfrac{382.59 \times 4.95}{288.09 \times 9.9} \right) \app

Which gives;

h = \mathbf{9.9 * sin\left(arctan \left(\dfrac{382.59 \times 4.95}{288.09 \times 9.9} \right) \right)} \approx 5.48

The minimum height below which the ladder will slip, h ≈ <u>5.48 m</u>

Learn more about friction here:

brainly.com/question/13879636

6 0
2 years ago
A horse pulls a wagon with a force of 200 N for a distance of 80 m. How much work
sergey [27]

Answer:

w=f×s

w = 16000 J, hope this helps

4 0
3 years ago
the initial kinetic energy of an object moving on a horizontal surface is K. Friction between the object and the surface causes
Ugo [173]

Answer:

........................

8 0
3 years ago
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