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damaskus [11]
4 years ago
10

Andrew kicks a ball along a straight path. The ball rolls straight forward for 13.2 meters. Then Andrew kicks the ball straight

back. The ball rolls back along the same path for 9.5 meters. What distance did the ball travel?
Physics
1 answer:
tresset_1 [31]4 years ago
7 0

Answer: 22.7 meters

Explanation: The distance traveled is how much the ball has rolled in total, this means the lenght of the path that it has followed from begining to end.

Since it first travels 13.2 meters and then 9.5 meters, if we sum this quantities:

13.2 + 9.5 = 22.7 meters

So 22.7 is the distance that the ball has traveled.

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The impulse given to a ball with mass of 4 kg is 16 N s. If the ball starts from rest, what is its final velocity?
photoshop1234 [79]
The formula for impulse is F*(t₂-t₁)=m*(v₂-v₁), where F is the force, t is time, m is mass and v is velocity. 

In our case m*(v₂-v₁)=16 N s, m=4 kg, v₁=0 and t₁=0.

m*(v₂-0)=16 N s, we solve for v₂:

4*v₂= 16

v₂=16/4

v₂=4 m/s

So the final velocity of the ball is v₂=4 m/s.
7 0
3 years ago
If you're falling in a forest and there's nobody around, do you ever really crash, or even make a sound?
zalisa [80]

Answer:

yes bc there are branches and twigs surrounding you

Explanation:

♡♡♡please mark as brainliest♡♡♡

7 0
3 years ago
Read 2 more answers
Can you fill those blanks with the correct word?
VikaD [51]
#1 is sand dune   ,  #2 glaciers   , #3 sand sediments hence small mass and #4 is <span> moraine .</span>
4 0
3 years ago
A beam of light strikes a sheet of glass at an angle of 57.0°. with the normal in air. You observe that red light makes an angle
Lena [83]

Answer:

a) Red: 1.34

Violet: 1.40

b) Red: 2.23\times10^8\frac{m}{s}

Violet: 2.14\times10^8\frac{m}{s}

Explanation:

a) We should use Snell's law to find the index of refraction:

n_{1}sin\theta_{i}=n_{2}sin\theta_{t}

with n1 the index of refraction of air, n2 the index of refraction of the glass, θi the angle of the incident ray respects the normal an θt the angle between the refracted ray an the normal. It's common to approximate n1=1

solving n2 for red light:

\frac{sin\theta_{i}}{sin\theta_{t}}=n_{2}

n_2=\frac{sin57.0}{sin38.1}= 1.34

solving n2 for violet light:

\frac{sin\theta_{i}}{sin\theta_{t}}=n_{2}

n_2=\frac{sin57.0}{sin36.7}= 1.40

b) Index of refraction on a medium is defined as the ratio between the velocity of electromagnetic waves on vacuum (velocity of light c) and the velocity in medium (v):

n_2=\frac{c}{v}

solving v for red:

v=\frac{c}{n_2}=\frac{3\times10^8}{1.34}=2.23\times10^8\frac{m}{s}

solving v for violet

v=\frac{c}{n_2}=\frac{3\times10^8}{1.40}=2.14\times10^8\frac{m}{s}

8 0
3 years ago
What is the kinetic energy of a toy truck with a mass of 0.75 kg and a velocity of 4 m/s? (Formula: )
Dvinal [7]

Answer: Option (b) is the correct answer.

Explanation:

Kinetic energy is the energy of an object or particle when it is in motion.

Mathematically,   Kinetic energy = \frac{1}{2}mass \times (velocity)^{2}

It is given that toy truck has mass = 0.75 kg, and velocity = 4 m/s.

Calculate the kinetic energy as follows.

           Kinetic energy = \frac{1}{2}mass \times (velocity)^{2}

                                    = \frac{1}{2}0.75 kg \times (4 m/s)^{2}

                                     = \frac{1}{2}0.75 kg \times 16 m^{2}/s^{2}

                                     = 0.75 kg \times 8 m^{2}/s^{2}

                                     =  6 kg m^{2}/s^{2}

or,       Kinetic energy = 6 joules

Thus, we can conclude that kinetic energy of toy truck is 6 J.


6 0
4 years ago
Read 2 more answers
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