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2 years ago

A sound wave travels at 379 m/sec and has a wavelength of 8 meters. Calculate its frequency and period.

Physics

1 answer:

olga nikolaevna [1]2 years ago

6 0

$\qquad\qquad\huge\underline{{\sf Answer}}$

Wavelength, Wavespeed and frequency depends on each other in the following way :

$\qquad \sf \dashrightarrow \: frequency = \dfrac{wave \: \: velocity}{wavelength}$

$\qquad \sf \dashrightarrow \: f = \dfrac{389}{8}$

$\qquad \sf \dashrightarrow \: f \approx 48.62 \: \: hertz$

And we know the Reciprocal relationship between frequency and period ~

So, let's find it's period •

$\sf{\qquad \sf \dashrightarrow \: t = \dfrac{8}{389}}$

$\sf{\qquad \sf \dashrightarrow \: t \approx 0.02 sec }$

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Find the ratio of the lengths of the two mathematical pendulums, if the ratio of periods is 1.5

juin [17]

Answer:

The ratio of lengths of the two mathematical pendulums is 9:4.

Explanation:

It is given that,

The ratio of periods of two pendulums is 1.5

Let the lengths be L₁ and L₂.

The time period of a simple pendulum is given by :

$T=2\pi \sqrt{\dfrac{l}{g}}$

$T^2=4\pi^2\dfrac{l}{g}\\\\l=\dfrac{T^2g}{4\pi^2}$

Where

l is length of the pendulum

$l\propto T^2$

$\dfrac{l_1}{l_2}=(\dfrac{T_1}{T_2})^2$ ....(1)

ATQ,

$\dfrac{T_1}{T_2}=1.5$

Put in equation (1)

$\dfrac{l_1}{l_2}=(1.5)^2\\\\=\dfrac{9}{4}$

So, the ratio of lengths of the two mathematical pendulums is 9:4.

3 0

3 years ago

6. A 2.2 kg rock rests on the edge of a bridge that is 3.3 m above a river. What is the

vovikov84 [41]

Answer: 71 J

Explanation: The formula for gravitational potential energy is Epg= mgh.

So you plug in 2.2 as m, 3.3 as h and 9.81 as g. Once you do that you should get an answer of 71.2206. But because there are only two significant digits in the question, your answer must also have two significant digits.

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4 years ago

While playing catch with my dog I bounced the ball off the ground at a 30-degree angle. It had a range of 6 meters.

baherus [9]

The initial velocity of the ball is 8.2 m/s

Explanation:

The motion of the ball is a projectile motion, which consists of two separate motions:

- A uniform motion along the horizontal direction, at constant velocity

- A uniformly accelerated motion along the vertical direction, with constant acceleration ( $g=9.8 m/s^2$ , acceleration of gravity)

The range of a projectile can be derived by the equation of motions along the two directions, and it is found to be:

$d=\frac{v^2 sin 2\theta}{g}$

where

v is the initial velocity of the projectile

$\theta$ is the angle of projection

g is the acceleration of gravity

For the ball in this problem, we have

$\theta=30^{\circ}$

d = 6 m is the range

Solving for v, we find the initial velocity:

$v=\sqrt{\frac{gd}{sin 2\theta}}=\sqrt{\frac{(9.8)(6)}{sin (2\cdot 30^{\circ})}}=8.2 m/s$

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

7 0

3 years ago

Electric current comes from the movement or flow of____ charged

Ivahew [28]

Answer:

negatively ,

That all I can help you.

7 0

3 years ago

A wave is traveling down a string at 15 m/s. A snapshot of the wave is shown in the figure below.

max2010maxim [7]

(a) Amplitude=1.5 m

Amplitude is the maximum distance from the mean (zero disturbance) position.Here amplitude= 1.5 m

(b) wavelength= 2 m

Wavelength is the length of one complete wave or distance traveled by a wave in a time equal to Time Period. Here wavelength= 2 m

using equation for wave velocity V= f λ

15= f (2)

f=7.5 Hz

so frequency=7.5 Hz

(d) Time period= 0.133 s

Time period= T= 1/f

T= 1/7.5

T=0.133 s

so time period=0.133 s

5 0

3 years ago