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Gala2k [10]
3 years ago
7

What is one reason for feeling warmer in your house on a summer day versus a winter day even though your thermostat is set the s

ame?
A. The walls of the house are warmer during the summer. Therefore, they radiate more infrared light that can serve to warm our body.
B. The walls of the house are warmer during the summer. Therefore, they radiate more visible light that can serve to warm our body.
C. The walls of the house are warmer during the summer. Therefore, they radiate more ultraviolet (UV) light that can serve to warm our body.
D. The temperature of the walls of the house has no effect on the light they radiate.
Physics
2 answers:
anzhelika [568]3 years ago
7 0
The correct option is C.
During the summer period, the weather is hotter compare to the winter period because the sun is closer to the earth. The walls of our houses absorb the more intense heat and radiate part of it into the house, this makes us to feel warmer.
goblinko [34]3 years ago
3 0
The best answer for this question would be, C.
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A 56 kg woman climbs the stairs to a height of 5 m. Determine: a) what mechanical work
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Answer:

a) W = 2746.8[J]

b) W = 2992.05 [J]

Explanation:

Work is defined as the product of force by distance. We must bear in mind that the force that performs the work is the one that acts in the same direction of displacement.

For this case, we must calculate the weight of the woman, the weight is defined as the product of mass by gravity.

w=m*g\\

where:

w = weight [N] (units of Newtons]

m = mass = 56 [kg]

g = gravity acceleration = 9.81 [m/s²]

w=56*9.81\\w=549.36[N]

a)

W=F*d

where:

F = weight = 549.36[N]

d = distance = 5 [m]

W = 549.36*5\\W = 2746.8[J]

b)

The new mass will be the combination of the mass of the woman plus that of the load.

m_{new} = 56+5\\m_{new}=61[kg]

w_{new}=61*9.81\\w_{new}=598.41[N]

The new work done.

W =598.41*5\\W=2992.05[J]

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3 years ago
How much force is needed to stop a 80-kg football player if he decelerates at 5 m/s2
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(b) Assuming h is small in comparison to the radius of the Earth, show that the difference in free-fall acceleration between two
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Vertical distance h isΔg=\frac{-2GM}{ RE^{3} }

<h3>What is vertical?</h3>
  • The distance between two vertical places is known as the vertical separation or vertical distance. There are numerous ways to express vertical position using vertical coordinates, including depth, height, altitude, elevation, etc.
  • The formula for vertical distance from the ground is y = - g * t2 / 2, where g is the acceleration of gravity and h is a height.
  • The vertical distance between the measurement point and the point of observation on Earth's surface. Altitude is the vertical distance from the measurement place to mean sea level.

Assuming h is small in comparison to the radius of the Earth, show that the difference in free-fall acceleration between two points separated by vertical distance h isΔg = (2GMeH) / RE³:

Given:

Separated between two points=h

And, h∠∠R_{E}           (R_{E}= radius of the Earth)

Now, \frac{dg}{dr} =\frac{-2GM}{ RE^{3} }

dg =\frac{-2GM}{ RE^{3} } dr

Δg=\frac{-2GM}{ RE^{3} }  

Therefore, Vertical distance h isΔg=\frac{-2GM}{ RE^{3} }  

To learn more about Vertical, refer to:

brainly.com/question/24261456

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