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Gala2k [10]
2 years ago
7

What is one reason for feeling warmer in your house on a summer day versus a winter day even though your thermostat is set the s

ame?
A. The walls of the house are warmer during the summer. Therefore, they radiate more infrared light that can serve to warm our body.
B. The walls of the house are warmer during the summer. Therefore, they radiate more visible light that can serve to warm our body.
C. The walls of the house are warmer during the summer. Therefore, they radiate more ultraviolet (UV) light that can serve to warm our body.
D. The temperature of the walls of the house has no effect on the light they radiate.
Physics
2 answers:
anzhelika [568]2 years ago
7 0
The correct option is C.
During the summer period, the weather is hotter compare to the winter period because the sun is closer to the earth. The walls of our houses absorb the more intense heat and radiate part of it into the house, this makes us to feel warmer.
goblinko [34]2 years ago
3 0
The best answer for this question would be, C.
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Katena32 [7]
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2 years ago
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Answer:

0.021 V

Explanation:

The average induced emf (E) can be calculated usgin the Faraday's Law:

E = - \frac{N*\Delta \phi}{\Delta t}  

<u>Where:</u>

<em>N = is the number of turns = 1   </em>

<em>ΔΦ = ΔB*A                                            </em>

<em>Δt = is the time = 0.3 s   </em>

<em>A = is the loop of wire area = πr² = πd²/4 </em>

<em>ΔB: is the magnetic field = (0 - 1.04) T                     </em>

Hence the average induced emf is:

E = - \frac{\Delta B*A}{\Delta t} = - \frac{(0- 1.04 T) \pi (0.088 m)^{2}}{4*0.3 s} = 0.021 V                      

Therefore, the average induced emf is 0.021 V.

I hope it helps you!

8 0
3 years ago
What is an instrument commonly used to measure wind speed?
xeze [42]
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5 0
2 years ago
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A trombone can produce pitches ranging from 85 Hz to 660 Hz approximately. When the trombone is producing a 562 Hz tone, what is
tester [92]

To solve this problem we will apply the concept of wavelength, which warns that this is equivalent to the relationship between the speed of the air (in this case in through the air) and the frequency of that wave. The air is in standard conditions so we have the relation,

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Speed of sound in air = v = 331m/s

The definition of wavelength is,

\lambda = \frac{v}{f}

Here,

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f = Frequency

Replacing,

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\lambda = 0.589m

Therefore the wavelength of that tone in air at standard conditions is 0.589m

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3 years ago
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Oksi-84 [34.3K]

Answer:

This would be 24 minutes

Explanation:

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