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jarptica [38.1K]
4 years ago
15

Answer all the following questions by putting a circle around a letter A.B.C or D

Chemistry
1 answer:
Nataly_w [17]4 years ago
3 0

Answer:

C. 21%oxygen

Explanation:

Dry air contains 78.09% nitrogen, 20.95%oxygen, 0.93% argon, 0.04% carbon dioxide, and small amounts of other gases.

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What is ""green chemistry""? Describe how the distillation procedure used in this lab is a more ""green"" approach than liquid-l
pshichka [43]

Answer: Green chemistry, can also be referred to as a major branch of Chemical Engineering that focuses on the nature plants for the use of new products and reduce wastage of resources.

Explanation:

The distillation apparatus used is open to the atmosphere to allow for removal of poisonous gas and absorption of some composition in the space for proper result.

5 0
4 years ago
PLEASE HELP WILL MARK BRAINLIEST!!!
lina2011 [118]

Answer:

#1. E

#2. A

#3. D

#4. F

#5. C

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5 0
3 years ago
Which of these is an example of food engineering
iogann1982 [59]
I don't know which ones r, could u add options, maybe?
3 0
4 years ago
Read 2 more answers
What volume of methane gas at 237 K and 101.33 kPa do you have when the volume is decreased to 0.50 L, with a temperature of 300
Alexxandr [17]

Answer: A volume of 0.592 L of methane gas is required at 237 K and 101.33 kPa when the volume is decreased to 0.50 L, with a temperature of 300 K and a pressure of 151.99 kPa.

Explanation:

Given: T_{1} = 237 K,   P_{1} = 101.33 kPa,      V_{1} = ?

T_{2} = 300 K,      P_{2} = 151.99 kPa,        V_{2} = 0.50 L

Formula used is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{101.33 kPa \times V_{1}}{237 K} = \frac{151.99 kPa \times 0.50 L}{300 K}\\V_{1} = 0.592 L

Thus, we can conclude that a volume of 0.592 L of methane gas is required at 237 K and 101.33 kPa when the volume is decreased to 0.50 L, with a temperature of 300 K and a pressure of 151.99 kPa.

8 0
3 years ago
You have 8 moles of a gas at 250 K in a 6 L container. What is the pressure of the gas? Show your work
Bogdan [553]

Hello:

In this case, we will use the Clapeyron equation:

P = ?

n = 8 moles

T = 250 K

R = 0.082 atm.L/mol.K

V = 6 L

Therefore:

P * V = n *  R * T

P * 6 = 8 * 0.082* 250

P* 6 = 164

P = 164 / 6

P = 27.33 atm


Hope that helps!

7 0
4 years ago
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