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jarptica [38.1K]
4 years ago
15

Answer all the following questions by putting a circle around a letter A.B.C or D

Chemistry
1 answer:
Nataly_w [17]4 years ago
3 0

Answer:

C. 21%oxygen

Explanation:

Dry air contains 78.09% nitrogen, 20.95%oxygen, 0.93% argon, 0.04% carbon dioxide, and small amounts of other gases.

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Major areas of science inclued_____.
xxTIMURxx [149]

Answer:

Human Biology

Chemistry

Physics

Explanation:

6 0
3 years ago
What is the formula for solid sodium metal reacts with solid iron (lll) chloride. Solid iron metal and solid sodium chloride are
sineoko [7]

Answer:

Explanation:When sodium metals reacts with iron (ll) chloride,iron metal and sodium chloride are formed. -2 Na(s)+fella(s) fev(s)+2Naci.

3 0
3 years ago
how many moles of iodine should be added to 750 grams of carbon tetrachloride to prepare a 0.24 m solution
aleksley [76]

Answer:

0.18 mol

Explanation:

Given data

  • Mass of carbon tetrachloride (solvent): 750 g
  • Molality of the solution: 0.24 m
  • Moles of iodine (solute): ?

Step 1: Convert the mass of the solvent to kilograms

We will use the relationship 1 kg = 1,000 g.

750g \times \frac{1kg}{1,000g} =0.750kg

Step 2: Calculate the moles of the solute

The molality is equal to the moles of solute divided by the kilograms of solvent. Then,

m = \frac{moles\ of\ solute }{kilograms\ of\ solvent} \\moles\ of\ solute = m \times kilograms\ of\ solvent = \frac{0.24mol}{kg}  \times 0.750kg = 0.18 mol

6 0
3 years ago
Read 2 more answers
How many bonding and nonbonding electrons are on the carbon atom in CO2?
il63 [147K]

Answer:

I believe the answer is B

Explanation:

to be honest i'm not completely sure, sorry

4 0
3 years ago
Read 2 more answers
Estimate the freezing and normal boiling points of 0.25 m aqueous solutions of nh4no3 nicl3 al2so43
maks197457 [2]
The items are answered below and are numbered separately for each compound. 

The freezing point of impure solution is calculated through the equation,
     Tf = Tfw - (Kf)(m)

where Tf is the freezing point, Tfw is the freezing point of water, Kf is the freezing point constant and m is the molality. For water, Kf is equal to 1.86°C/m. In this regard, it is assumed that m as the unit of 0.25 is molarity.

1. NH4NO3
    Tf = 0°C - (1.86°C/m)(0.25 M)(2) = -0.93°C

2. NiCl3 
    Tf = 0°C - (1.86°C/m)(0.25 M)(4) = -1.86°C

3. Al2(SO4)3
      Tf = 0°C - (1.86 °C/m)(0.25 M)(5) = -2.325°C

For boiling points, 
    Tb = Tbw + (Kb)(m)
For water, Kb is equal to 0.51°C/m.

1. NH4NO3
     Tb = 100°C + (0.51°C/m)(0.25 M)(2) = 100.255°C

2. NiCl3
     Tb = 100°C + (0.51°C/m)(0.25 M)(4) = 100.51°C

3. Al2(SO4)3
    Tb = 100°C + (0.51°C/m)(0.25 M)(5) = 100.6375°C
7 0
4 years ago
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