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marta [7]
3 years ago
6

Can you please help me I really need help please

Mathematics
1 answer:
sveta [45]3 years ago
4 0

so they make 88 computers every day

that would mean each day = 88 computers

if d is day and c is computer

the equation is d=88c

Maybe try filling out the chart on your own?? I feel like at this point I'm not actually helping you understand the concept. I'm not really comfortable with just giving you the answers...

sorry : (

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38) The length of a rectangle is 15.6 cm correct to 1 decimal place.
Ede4ka [16]

Answer:

38.75

Step-by-step explanation:

perimeter = 2(15.6+3.8) =38.8

lower bound = the smallest value that would round up to the estimated value =38.75

6 0
3 years ago
Five students divided 74 base-ten rods equally among them. how many base-ten rods were left over?
lesya [120]

Answer:

Idont know that question

8 0
3 years ago
Please helpp will give brainliest
Alla [95]
Answer :

Length of rectangle = 14m

Width of rectangle = 12m

Explanation :

p = 2l + 2w = 68

l = w + 2

Substitute:

68 = 2(w + 2) + 2w

68 = 2w + 4 + 2w

4w = 64

w = 16

l = 18


I hope this helped out, have a nice day! :D



(P.s. Both taken from source)

8 0
3 years ago
What is the answer to -3 to the second power + 4.6 times -0.1
vagabundo [1.1K]
The answer is -9.46 yeah i think thats correct
8 0
3 years ago
Read 2 more answers
The number of students who attended FPM in 2015 was 1380. In 2016, 1405 students attended FPM. what was the percent of change in
Fittoniya [83]

The percent of change in student enrollment is 1.81 % increase

<em><u>Solution:</u></em>

Given that, The number of students who attended FPM in 2015 was 1380

In 2016, 1405 students attended FPM

To find: Percent change

<em><u>The percent change is given by formula:</u></em>

\text { percent change }=\frac{\text { final value - initial value}}{\text { initial value }} \times 100

If the result is positive, it is percent increase

If the result is negative, it is percent decrease

From given,

Initial value in 2015 = 1380

Final value in 2016 = 1405

<em><u>Substituting the values in formula, we get</u></em>

<em><u></u></em>\text { percent change }=\frac{1405-1380}{1380} \times 100\\\\\text { percent change }=\frac{25}{1380} \times 100\\\\\text { percent change }= 0.01811 \times 100\\\\\text { percent change }= 1.81<em><u></u></em>

Thus percent of change in student enrollment is 1.81 % increase

6 0
3 years ago
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