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astra-53 [7]
3 years ago
7

A pump separates out Argon atoms from all other atoms in air. If a bottle contains 8.34 x 10^22 atoms of argon what is the mass

of the air in the bottle? Can someone please help me learn how to convert this thing?
Chemistry
1 answer:
puteri [66]3 years ago
7 0

Answer:

55.4g

                                           

Explanation:

Given parameters:

Number of atoms in the bottle = 8.34 x 10²²atoms

Unknown:

Mass of air in the bottle  = ?

Solution:

The given specie is argon.

 Molecular mass of Argon  = 40g/mol

To find the mass of this Argon ;

          Mass  = number of moles x molecular mass;

  Let us find the number of moles of the Argon;

             6.02 x 10²³ atoms can be found in 1 mole of any substance

             8.34 x 10²² atoms will give \frac{8.34 x 10^{22} }{6.02 x 10^{23} }  mole of Argon

                                                        = 0.139mole of Argon

So;

       Mass of argon  = 40g/mol x 0.139mole  = 55.4g

                                           

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Finally, we shall determine the volume of the diluted solution. This can be obtained as follow:

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Volume of stock solution (V₁) = 2 L

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5 0
2 years ago
The molar mass of O2 is 32.0 g/mol.what mass,in grams,of O2 is required to react completely with 4.00 mol of Mg
Dahasolnce [82]
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What is the empirical formula of a compound that contains 75% Ag and 25% Cl by mass
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Explanation:

Data

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2.- Calculate the moles of each element

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                            108 g of Ag ------------------  1 mol

                              75 g of Ag ------------------   x

                                x = (75 x 1) / 108

                                x = 75 / 108

                                x = 0.69 moles

                            35.5 g of Cl ------------------ 1 mol

                             25 g of Cl    -----------------   x

                                    x = (25 x 1) / 35.5

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3.- Divide by the lowest number of moles

Ag = 0.69/0.69 = 1

Cl = 0.70 / 0.69 = 1.02 ≈ 1

4.- Write the empirical formula

                                                 Ag₁ Cl₁  = AgCl

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