Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to

sq. units.
Answer:
http://www.classzone.com/science_book/mls_grade6_FL/540_547.pdf
Step-by-step explanation:
Answer:
x = -22
Step-by-step explanation:
2(5– x)3 – 11 = 151
(10 - 2x)3 - 11 = 151
30 - 6x = 162
-6x = 132
x = -22
The value of x is 2. hope it helps!