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Alchen [17]
2 years ago
6

The average human reaction time from eye to finger is 0.16 second. How is this expressed as a fraction?

Mathematics
1 answer:
xxTIMURxx [149]2 years ago
6 0

Answer:

4/25 seconds

Step-by-step explanation:

the second (0.16) is in two decimal places, so divide 16 by 100

\frac{16}{100}

to express in the simplest form, divide the numerator  and the denominator by 4

= \frac{4}{25}

You might be interested in
A car rental agency Advertise renting a car for $24.95 per day and $.33 per mile is Kevin rent the car for today how many whole
pychu [463]

Answer:

Kevin can drive 681 miles.

Step-by-step explanation:

In order to find the amount that he can drive in one day and only pay $250, we have to write an equation for the cost. Using x as the miles he drive, we can express the equation as:

y = .33x + 24.95

Now, we can plug in 250 for y.

250 = .33x + 24.95

225.05 = .33x

681.97 = x

Since we are looking for only whole miles, we have to round down to 681.

6 0
2 years ago
A bridge 48m tall.a scale model of the bridge 37cm long and 12cm tall .how long is the actual bridge .
Roman55 [17]
\frac{48m}{x}=\frac{37cm}{12cm}

37x=48*12

37x=576

x=<span>15.57m long.

The bridge is about 16 meters long.
</span>
6 0
3 years ago
Which of the following is not a possible number of solutions when solving a system of equations containing a quadratic and a lin
Kobotan [32]

Answer:

3

Step-by-step explanation:

We have a system with two equations, one equation is a quadratic function and the other equation is a linear function.

To solve this system we have to clear "y" in both equations, and then equal both equations, then we will have a quadratic function and equal it to zero:

ax^2+bx+c=0, a\neq 0

Then to resolve a quadratic equation we apply Bhaskara's formula:

x_{1}=\frac{-b+\sqrt{b^2-4ac} }{2a}

x_{2}=\frac{-b-\sqrt{b^2-4ac} }{2a}

It usually has two solutions.

But it could happen that \sqrt{b^2-4ac} then the equation doesn't have real solutions.

Or it could happen that there's only one solution, this happen when the linear equation touches the quadratic equation in one point.

And it's not possible to have more than 2 solutions. Then the answer ir 3.

For example:

In the three graphs the pink one is a quadratic function and the green one is a linear function.

In the first graph we can see that the linear function intersects the quadratic function in two points, then there are two solutions.

In the second graph we can see that the linear function intersects the quadratic function in only one point, then there is one solutions.

In the third graph we can see that the linear function doesn't intersect the quadratic function, then there aren't real solutions.

7 0
3 years ago
HELP IN NEED!
laiz [17]

Answer:

AB=12\sqrt{3}\ cm

Step-by-step explanation:

If AB is tangent to the circle, then angle ABO is right angle and triangle AOB is special 30^{\circ}-60^{\circ}-90^{\circ} triangle. In this triangle, the leg that is opposite to the angle of 30° is half of the hypotenuse. Thus,

AO=2BO=2\cdot 12=24\ cm.

By the Pythagorean theorem,

AB^2=AO^2-BO^2,\\ \\AB^2=24^2-12^2,\\ \\AB^2=576-144=432,\\ \\AB=12\sqrt{3}\ cm.

6 0
2 years ago
Help plz (problly easy for you)
PolarNik [594]

The second option: 4x² - x + 1

All you have to do is add the like terms:

3x² + x² = 4x²

4x - 5x = -x

-2 + 3 = 1

Combine all the results and you will get your solution!

6 0
3 years ago
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