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grin007 [14]
3 years ago
5

How to solve r-9≤-25​

Mathematics
1 answer:
nataly862011 [7]3 years ago
4 0

Answer:

Step-by-step explanation:

That’s the answer (the pic)

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-|8|—|11-8| complute the value of the given expression
drek231 [11]

-8 - 11+ 8    

i believe this is the answer i havnt done this in a long time

5 0
3 years ago
The surface area of the rectangular prism below is 286in2. Find the height.
Rudiy27

Answer: 7in

Step-by-step explanation:

Formula: A=2(wl+hl+hw)

Solve for h;

Let's begin by dividing by 2.

\frac{A}{2}=wl+hl+hw

Subtract wl because it's the only term that doesn't have h.

\frac{A}{2}-wl=hl+hw

Plug your values into the formula.

\frac{286in^2}{2}-(5in)(9in) =h(9in)+h(5in)\\143in^2-45in^2=9inh+5inh\\98in^2=14inh

Divide by 14 to isolate h.

\frac{98in^2}{14in}=h

7in=h

4 0
3 years ago
a pet store owner set the price of a bag of cat food at 50% above the cost. when it did not sell, the price was reduced 20% to 1
Ilya [14]

Answer:

cost = $10

Step-by-step explanation:

let cost be x

Price = x+ (0.5x)= 1.50x

cost reduced in term of x is 20% of 1.50x

\frac{20}{100} * 1.50x = 0.3x

hence 1.50x - 0.3x = 12

1.2x=12

x= \frac{12}{1.2} = 10

cost = $10

8 0
3 years ago
An object is launched directly upward with an initial velocity of 64 feet per second from a platform 80 feet high. What will be
LekaFEV [45]

Answer:

a) 63.6 ft

b) 1.99 seconds

c) 4.98 seconds

Step-by-step explanation:

a) The object will reach maximum height when its final velocity, v, is 0 m/s.

We apply one of Newton's equations of motion to solve this:

v^2 = u^2 - 2gh

where u = initial velocity = 64 ft/s

g = acceleration due to gravity = 32.2 ft/s

h = height reached by object.

Note: the equation has a negative sign because the object is going upwards, against gravity.

Hence:

0^2 = 64^2 - 2*32.2*h\\\\=> 64.4h = 4096\\\\h = 4096 / 64.4\\\\h = 63.6 ft

The object is now 63.6 ft above the platform (143.6 ft above the ground).

b) Time taken to get to that height can be gotten by using another one of Newton's equations:

v = u - gt

=> 0 = 64 - 32.2t

32.2t = 64\\\\=> t = 64 / 32.2 \\\\t = 1.99 secs

It took the object 1.99 secs to get to that height.

c) When the object begins falling to ground level, it is at a height, h =  143.6 ft and begins moving at initial velocity, u = 0 m/s.

Applying another of Newton's equations of motion, we have that:

h = ut + \frac{1}{2}gt^2

where t is the time taken to hit the floor after it begins its descent.

Therefore,

143.6 = 0*t + \frac{1}{2}*32.2t^2\\ \\143.6 = 16.1t^2\\\\t^2 = 143.6 / 16.1\\\\t^2 = 8.92\\\\t = \sqrt{8.92} \\\\t = 2.99 secs

This is the time it will take the object to hit the floor after it begins its descent.

Therefore, the total time it will take for the object to hit the ground after it is launched will be:

T = time taken to reach maximum height + time taken to hit the floor after it begins descending

T = 1.99 + 2.99

T = 4.98 seconds

6 0
3 years ago
The library had 124,000 books find how many books are classified as children fiction l
Mrrafil [7]
Take 124,000 books and multiply it by the percentage of children fiction which is 23%

124,000 x 0.23 = 28,520 children fiction books
6 0
3 years ago
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