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stich3 [128]
3 years ago
9

The price of stock a.m. 9 AM was $12.73 cents and the price has been increasing at the rate of six cents per hour at noon the pr

ice of stock to you is $13.48 Ginza decrease at the rate of $.14 per hour if the stocks continue to increase and decrease at the same rate in how many hours are the prices of stock to be the same
Mathematics
1 answer:
svp [43]3 years ago
7 0

Sry couldn't find the answer

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Using synthetic division, find (2x4 + 4x3 + 2x2 + 8x + 8) ÷ (x + 2).
creativ13 [48]
The answer is 32x+8
————
x+2
5 0
3 years ago
What is n/8=11/5 solve for n<br><br><br> #youngboy comment
mihalych1998 [28]

n should be 8 according to mathmatical laws

8 0
3 years ago
C=27+10h where c= cost in dollars and h= number of hours rented ​
gavmur [86]

Answer:

that help

Step-by-step explanation:

10h+27+−27=c+−27

10h=c−27

10h10=c−2710

h=110c+−2710

Answer:

h=110c+−2710

3 0
3 years ago
Can I please have help?
jok3333 [9.3K]

Answer:

(-3, 3) and (8, -8)

Step-by-step explanation:

having the rule (x + 3, y – 5) and an input point (x,y) you just plu th iput point into the rule and you will get the output point.

With an input point (-6,8) you plug -6 in for x and 8 in for y into the rule.  

(x + 3, y – 5)

(-6 + 3, 8 - 5)

(-3, 3)

Now we do the same for (5, -3) as the input

(x + 3, y – 5)

(5 + 3, -3 - 5)

(8, -8)

4 0
3 years ago
√₂
snow_lady [41]

Answer:

$2000 was invested at 5% and $5000 was invested at 8%.

Step-by-step explanation:

Assuming the interest is simple interest.

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned.
  • P = principal invested.
  • r = interest rate (in decimal form).
  • t = time (in years).

Given:

  • Total P = $7000
  • P₁ = principal invested at 5%
  • P₂ = principal invested at 8%
  • Total interest = $500
  • r₁ = 5% = 0.05
  • r₂ = 8% = 0.08
  • t = 1 year

Create two equations from the given information:

\textsf{Equation 1}: \quad \sf P_1+P_2=7000

\textsf{Equation 2}: \quad \sf P_1r_1t+P_2r_2t=I\implies 0.05P_1+0.08P_2=500

Rewrite Equation 1 to make P₁ the subject:

\implies \sf P_1=7000-P_2

Substitute this into Equation 2 and solve for P₂:

\implies \sf 0.05(7000-P_2)+0.08P_2=500

\implies \sf 350-0.05P_2+0.08P_2=500

\implies \sf 0.03P_2=150

\implies \sf P_2=\dfrac{150}{0.03}

\implies \sf P_2=5000

Substitute the found value of P₂ into Equation 1 and solve for P₁:

\implies \sf P_1+5000=7000

\implies \sf P_1=7000-5000

\implies \sf P_1 = 2000

$2000 was invested at 5% and $5000 was invested at 8%.

Learn more about simple interest here:

brainly.com/question/27743947

brainly.com/question/28350785

5 0
1 year ago
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