Answer:
a) tD = 4.36 sec
b) tD = 5.2 sec
Explanation:
a)
V = 0
work-done = change in kinetic energy
f.m.g(d) = 1/2m(55^2 - v^2)
divided both sides by m
1/2(55^2 - v^2) = f.g(d)
1/2(55 * 1.467)^2 ft^2/sec^2 = 0.6 * (9.81 * 3.28) * d
3255.03 = 19.306d
d = 3255.03 / 19.306
d = 168.6 ft
now D = 520 - 168.6 = 351.4
therefore reaction/perception time = tD
tD = 351.4 / ( 55 * 1.467)
tD = 4.36 sec
b)
Also here, V = 35 mph
so
1/2(55^2 - 35^2)*(1.467)^2 ft^2/sec^2) = 0.6 * (9.81 * 3.28) * d
1936.88 = 19.306d
d = 1936.88 / 19.306
d = 100.325ft
also D = 520ft - 100.325ft = 419.675
so tD = 419.675 / ( 55 * 1.467)
tD = 5.2 sec
Answer:
n = 2r³/Rd²
Explanation:
See the attached file for the derivation.
Answer:
what does that mean welp I have no idea sorry for answering
Answer:
Check the 2nd, 3rd and 4th statements.
Explanation:
