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IRISSAK [1]
3 years ago
12

Why did fprtmiu78t7ty87uhyu

Engineering
1 answer:
alekssr [168]3 years ago
6 0
Yea why did fprtmiu78t7ty87uhyu
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Discuss the chemical and physical properties of crude oil​
mr Goodwill [35]

Answer:

Denser and more viscous crude oils have greater concentrations of other components, including resins and asphaltenes, which contain more polar compounds, often including “heteroatoms” of nitrogen, sulfur, and oxygen as well as carbon and hydrogen.

7 0
4 years ago
Give six reasons why farmers cultivate on small land​
scoray [572]

Ans:

1.some families of farmers are poor so they are forced to cultivate on small lands.

2.farmers have not enough resources to keep good care of the crops.

3.land nowadays is so expensive that they afford a small piece of land to cultivate.

4.farmers need helpers when there are no helpers, the farmers need to make there land small in order to cultivate.

Explanation:

i was just able to write 4 sorry. :(

8 0
3 years ago
An actual vapour compression system comprises following process represents a. 1-2 Compression process b. 2-3 Condens 1 (or heat
Gemiola [76]

Answer:

Explanation:

The deatailed diagram of VCRS is given below such

1-2=Isentropic compression in which temperature increases at constant entropy

2-3=Isobaric heat rejection i.e. heat rejected at constant pressure(condensation)

3-4=Irreversible expansion or throttling in which enthalpy remains constant

4-1=Isobaric heat addition(Evaporation)

4 0
3 years ago
10. Identify one material we Mine and what we make with that material
Katen [24]

Answer:

We Mine Limestone. Its used to make cement, toothpaste or paints, soil conditioner, and rip rap stone.

Explanation:

7 0
3 years ago
A certain heat pump produces 200 kW of heating for a 293 K heated zone while only using 75 kW of power and a heat source at 273
vodka [1.7K]

Answer:

COP(heat pump) = 2.66

COP(Theoretical maximum) = 14.65

Explanation:

Given:

Q(h) = 200 KW

W = 75 KW

Temperature (T1) = 293 K

Temperature (T2) = 273 K

Find:

COP(heat pump)

COP(Theoretical maximum)

Computation:

COP(heat pump) = Q(h) / W

COP(heat pump) = 200 / 75

COP(heat pump) = 2.66

COP(Theoretical maximum) = T1 / (T1 - T2)

COP(Theoretical maximum) = 293 / (293 - 273)

COP(Theoretical maximum) = 293 / 20

COP(Theoretical maximum) = 14.65

8 0
4 years ago
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