Answer:44.61 KJ
Explanation:
Let h_1,V_1,Z_1 be the initial specific enthalpy,velocity&elevation of the system
and h_2,V_2,Z_2 be the Final specific enthalpy,velocity&elevation of the system
mass(m)=7kg
Applying Steady Flow Energy Equation
![m\left [ h_1+\frac{v_1^2}{2g}+gZ_1\right ]](https://tex.z-dn.net/?f=m%5Cleft%20%5B%20h_1%2B%5Cfrac%7Bv_1%5E2%7D%7B2g%7D%2BgZ_1%5Cright%20%5D)
+Q=![\left [ h_2+\frac{v_2^2}{2g}+gZ_2\right ]](https://tex.z-dn.net/?f=%5Cleft%20%5B%20h_2%2B%5Cfrac%7Bv_2%5E2%7D%7B2g%7D%2BgZ_2%5Cright%20%5D)
+W
substituting values
![7\left [ h_1+\frac{13^{2}}{2g}+gZ_1\right ]+7\times2](https://tex.z-dn.net/?f=7%5Cleft%20%5B%20h_1%2B%5Cfrac%7B13%5E%7B2%7D%7D%7B2g%7D%2BgZ_1%5Cright%20%5D%2B7%5Ctimes2)
= ![\left [ h_2+\frac{23^2}{2g}+gZ_2\right ]](https://tex.z-dn.net/?f=%5Cleft%20%5B%20h_2%2B%5Cfrac%7B23%5E2%7D%7B2g%7D%2BgZ_2%5Cright%20%5D)
+W
W=![7\left [h_1-h_2+\frac{V_1^2-V_2^2}{2000g}+g\frac{\left (Z_1-Z_2 \right )}{1000}\right ]](https://tex.z-dn.net/?f=7%5Cleft%20%5Bh_1-h_2%2B%5Cfrac%7BV_1%5E2-V_2%5E2%7D%7B2000g%7D%2Bg%5Cfrac%7B%5Cleft%20%28Z_1-Z_2%20%5Cright%20%29%7D%7B1000%7D%5Cright%20%5D)
+Q
W=![7\left [4+\frac{13^2-23^2}{2000g}+g\frac{\left (40 \right )}{1000}[\right ]](https://tex.z-dn.net/?f=7%5Cleft%20%5B4%2B%5Cfrac%7B13%5E2-23%5E2%7D%7B2000g%7D%2Bg%5Cfrac%7B%5Cleft%20%2840%20%5Cright%20%29%7D%7B1000%7D%5B%5Cright%20%5D)
+
W=44.61KJ
Answer:
for 5.6V 9 turns, for 12.0V 19 turns, for 480V 755 turns
Explanation:
Vp/Vs= Np/Ns
Vp: Primary voltage
Vs: Secondary Voltage
Np: number of turns on primary side
Ns: number of turns on secondary side
for output 5.6V
140/5.6= 220/Ns
Ns= 8.8 or 9 Turns
for output 12.0V
140/12= 220/Ns
Ns= 18.9 or 19 turns
for output 480V
140/480= 220/Ns
Ns= 754.3 or 755 turns
False? i think false yes false
